Python词典列表的键和

Question

可能重复:
如何对dict元素求和

我有一个字典列表如下:

[{'Name': 'A', 'amt':100},
 {'Name': 'B', 'amt':200},
 {'Name': 'A', 'amt':300},
 {'Name': 'C', 'amt':400},
 {'Name': 'C', 'amt':500},
 {'Name': 'A', 'amt':600}]

我想总结amt每个name并在dict列表中得到以下结果:

 [{'Name':'A', 'amt':1000},
  {'Name':'B', 'amt':200},
  {'Name':'C', 'amt':900}]

Answer 1

from collections import defaultdict

c = defaultdict(int)
for d in list_of_dictionaries:
    c[d['Name']] += d['amt']

它产生c:

{'A': 1000, 'C': 900, 'B': 200}

要将其转换为词典列表:

[{'Name': name, 'amt': amt} for name, amt in c.items()]

结果:

[{'Name': 'A', 'amt': 1000}, {'Name': 'C', 'amt': 900}, {'Name': 'B', 'amt':200}]

Answer 2

另一种可能的解决方案,这次使用itertools:

lst = [
{'Name': 'A', 'amt':100},
{'Name': 'B', 'amt':200},
{'Name': 'A', 'amt':300},
{'Name': 'C', 'amt':400},
{'Name': 'C', 'amt':500},
{'Name': 'A', 'amt':600}]

import itertools as it
keyfunc = lambda x: x['Name']

groups = it.groupby(sorted(lst, key=keyfunc), keyfunc)
[{'Name':k, 'amt':sum(x['amt'] for x in g)} for k, g in groups]