Dav*_*ave 7 java activemq-classic
我有一个用Java编写的单线程ActiveMQ使用者.我要做的就是从队列中接收()一个消息,尝试将其发送到Web服务,如果成功则确认()它.如果Web服务调用失败,我希望消息保留在队列中并在超时后重新发送.
除了重新发送部分之外,它或多或少都在工作:每次重新启动我的消费者时,它会为仍然在队列中的每个消息收到一条消息,但是在发送它们之后,消息永远不会被重新发送.
我的代码看起来像:
public boolean init() throws JMSException, FileNotFoundException, IOException {
ActiveMQConnectionFactory connectionFactory = new ActiveMQConnectionFactory(user, password, url);
RedeliveryPolicy policy = new RedeliveryPolicy();
policy.setInitialRedeliveryDelay(500);
policy.setBackOffMultiplier(2);
policy.setUseExponentialBackOff(true);
connectionFactory.setRedeliveryPolicy(policy);
connectionFactory.setUseRetroactiveConsumer(true); // ????
Connection connection = connectionFactory.createConnection();
connection.setExceptionListener(this);
connection.start();
session = connection.createSession(transacted, ActiveMQSession.INDIVIDUAL_ACKNOWLEDGE);
destination = session.createQueue(subject); //???
consumer = session.createConsumer(destination);
//consumer.setMessageListener(this); // message listener had same behaviour
}
private void process() {
while(true) {
System.out.println("Waiting...");
try {
Message message = consumer.receive();
onMessage(message);
} catch (JMSException e) {
e.printStackTrace();
}
try {
Thread.sleep(500);
} catch (InterruptedException e) {
e.printStackTrace();
}
}
}
@Override
public void onMessage(Message message) {
System.out.println("onMessage");
messagesReceived++;
if (message instanceof TextMessage) {
try {
TextMessage txtMsg = (TextMessage) message;
String msg = txtMsg.getText();
if(!client.sendMessage(msg)) {
System.out.println("Webservice call failed. Keeping message");
//message.
} else {
message.acknowledge();
}
if (transacted) {
if ((messagesReceived % batch) == 0) {
System.out.println("Commiting transaction for last " + batch + " messages; messages so far = " + messagesReceived);
session.commit();
}
}
} catch (JMSException e) {
e.printStackTrace();
}
}
}
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我目前没有使用交易(也许我应该这样做?).
我确定我错过了一些简单的东西,很快就会拍打我的额头,但我似乎无法弄清楚这是怎么回事.谢谢!
编辑:由于代表不够,我自己无法回答:
好的,经过一些实验,事实证明交易是实现这一目标的唯一方法.这是新代码:
public boolean init() throws JMSException, FileNotFoundException, IOException {
ActiveMQConnectionFactory connectionFactory = new ActiveMQConnectionFactory(user, password, url);
RedeliveryPolicy policy = new RedeliveryPolicy();
policy.setInitialRedeliveryDelay(1000L);
policy.setMaximumRedeliveries(RedeliveryPolicy.NO_MAXIMUM_REDELIVERIES);
connectionFactory.setRedeliveryPolicy(policy);
connectionFactory.setUseRetroactiveConsumer(true);
Connection connection = connectionFactory.createConnection();
connection.setExceptionListener(this);
connection.start();
session = connection.createSession(transacted, ActiveMQSession.CLIENT_ACKNOWLEDGE);
destination = session.createQueue(subject);
consumer = session.createConsumer(destination);
}
@Override
public void onMessage(Message message) {
System.out.println("onMessage");
messagesReceived++;
if (message instanceof TextMessage) {
try {
TextMessage txtMsg = (TextMessage) message;
String msg = txtMsg.getText();
if(client.sendMessage(msg)) {
if(transacted) {
System.out.println("Call succeeded - committing message");
session.commit();
}
//message.acknowledge();
} else {
if(transacted) {
System.out.println("Webservice call failed. Rolling back message");
session.rollback();
}
}
} catch (JMSException e) {
e.printStackTrace();
}
}
}
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现在,按照"重新传递策略"中的指定,每1000毫秒重新发送一条消息.
希望这有助于其他人!:)
您不必使用事务,CLIENT_ACK/Session.recover() 也可以工作......
当发生以下任一情况时,消息将重新传送到客户端:
- 使用事务处理会话并调用 rollback()。
- 事务会话在调用提交之前关闭。
- 会话正在使用 CLIENT_ACKNOWLEDGE 并调用 Session.recover()。
请参阅http://activemq.apache.org/message-redelivery-and-dlq-handling.html
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