我很难做到以下几点:
select a.FirstName, a.LastName, v.District
from AddTbl a order by Firstname
inner join (select distinct LastName from
ValTbl v where a.LastName = v.LastName)
Run Code Online (Sandbox Code Playgroud)
我想在ValTbl上进行连接,但仅针对不同的值.
kol*_*kol 13
试试这个:
select distinct a.FirstName, a.LastName, v.District
from AddTbl a
inner join ValTbl v
on a.LastName = v.LastName
order by a.FirstName;
Run Code Online (Sandbox Code Playgroud)
或者这个(它做的相同,但语法不同):
select distinct a.FirstName, a.LastName, v.District
from AddTbl a, ValTbl v
where a.LastName = v.LastName
order by a.FirstName;
Run Code Online (Sandbox Code Playgroud)
Nate,我认为您实际上为问题中的正确答案提供了一个良好的开端(您只需要正确的语法)。我也有同样的问题,将DISTINCT放在子查询中确实比这里提出的其他答案要便宜。
select a.FirstName, a.LastName, v.District
from AddTbl a
inner join (select distinct LastName, District
from ValTbl) v
on a.LastName = v.LastName
order by Firstname
Run Code Online (Sandbox Code Playgroud)