Android GridView单击未被检测到

Question

我有以下LinearLayout用GridView它:

<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
    android:layout_width="match_parent"
    android:layout_height="match_parent"
    android:orientation="vertical" >

    <GridView
        android:id="@+id/songs_grid"
        android:layout_width="fill_parent"
        android:layout_height="fill_parent"
        android:clickable="true"
        android:columnWidth="250dp"
        android:gravity="center"
        android:horizontalSpacing="10dp"
        android:numColumns="auto_fit"
        android:verticalSpacing="10dp" />

</LinearLayout>

该GridView数据由一个定制适配器(使用简单的提供ViewHolder):

public class SongsAdapter extends BaseAdapter {

    private Context context;

    private LayoutInflater mInflater;

    private ArrayList<Song> songList;

    public SongsAdapter(Context context, ArrayList<Song> songList)
    {
        this.context = context;

        this.songList = songList;

        mInflater = LayoutInflater.from(this.context);
    }

    @Override
    public int getCount()
    {
        return songList.size();
    }

    public Object getItem(int position)
    {
        return songList.get(position);
    }

    public long getItemId(int position)
    {
        return position;
    }

    @Override
    public View getView(int position, View convertView, ViewGroup parent)
    {
        SongViewHolder viewHolder;

        if (convertView == null)
        {
            convertView = mInflater.inflate(R.layout.song_list_item, null);

            viewHolder = new SongViewHolder();

            //Get Views from Layout Template
            viewHolder.AlbumArt = (ImageView)convertView.findViewById(R.id.albumart);
            viewHolder.Title = (TextView)convertView.findViewById(R.id.title);
            viewHolder.Artist = (TextView)convertView.findViewById(R.id.artist);
        }
        else
        {
            viewHolder = (SongViewHolder) convertView.getTag();
        }

        Song song = songList.get(position);

        Bitmap bitmap = song.getAlbumArt();
        Bitmap missing = BitmapFactory.decodeResource(context.getResources(), R.drawable.albumart_missing);

        Bitmap albumArt = bitmap == null ? missing  : bitmap;

        viewHolder.AlbumArt.setImageBitmap(albumArt);
        viewHolder.Title.setText(song.getTitle());
        viewHolder.Artist.setText(song.getArtist());

        convertView.setTag(viewHolder);

        return convertView;
    }
}

当应用程序启动时,它会获得一个歌曲列表(来自xml,但目前正在使用手动输入的列表)并将其传递给我的适配器,然后设置OnItemClickListener:

GridView gridView = (GridView) findViewById(R.id.songs_grid);
gridView.setAdapter(new SongsAdapter(this, fk.getSongList()));

gridView.setOnItemClickListener(new OnItemClickListener()
{
    @Override
    public void onItemClick(AdapterView<?> parent, View view, int position, long id)
    {
        LinearLayout layout = (LinearLayout)view;

        TextView songTitle = (TextView)layout.findViewById(R.id.song_title);

        Song song = fk.getSong((String) songTitle.getText());

        if(song != null)
        {
            Intent play = new Intent(getBaseContext(), Play.class);
            startActivity(play);
        }
    }
});

当我第一次实现这个代码时,它一切正常,我相信我没有改变任何东西.如果太长,我试图让歌曲标题的文本以大字幕形式滚动,但是无法使其正常工作.在此阶段,我发现点击停止了工作.我现在删除了(我相信)所有代码,但它仍然失败.

当我触摸/点击(无论你怎么称呼它)都没有任何反应.没有任何错误.

我的代码有什么问题会导致这个问题吗？

Answer 1

检查您的项目布局.如果任何song_list_item布局视图被标记为可点击,则它们将阻止网格的onclick侦听器响应.

Answer 2

确保clickableGridView中的-attribute不会覆盖视图中项目的单击事件.