Django:基数为10的int()的文字无效

qli*_*liq 30 django exception

我是Django的新手并试图将作者姓名传递给视图并根据作者姓名过滤出引用对象.这是代码:

models.py

class Author(models.Model):
    author_name = models.CharField(max_length=50, default='unknown')
    author_info = models.TextField(max_length=1000)


class Quote(models.Model):
    author = models.ForeignKey(Author)
    quote = models.TextField(max_length=500)
    category= models.ForeignKey(Category)
    pub_date = models.DateTimeField('date published')
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urls.py:

url(r'^quotes/(?P<name>\w+)/$', 'quotes.views.quotesbyauthor'),
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views.py

def quotesbyauthor(request, name):
    aquotelist = Quote.objects.filter(author__exact = name)
    return render_to_response(quotes_by_author.html, {'aquotelist': aquotelist })
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但是当我尝试获取http://127.0.0.1:8000/quotes/you/ ('你'是测试作者对象,已经创建)时,我收到此错误

ValueError at /quotes/you/

invalid literal for int() with base 10: 'you'

Request Method:     GET
Request URL:    http://127.0.0.1:8000/quotes/you/
Django Version:     1.3.1
Exception Type:     ValueError
Exception Value:    

invalid literal for int() with base 10: 'you'

Exception Location:     /home/qliq/djenv/lib/python2.6/site-packages/django/db/models/fields/__init__.py in get_prep_value, line 479
Python Executable:  /home/qliq/djenv/bin/python
Python Version:     2.6.6
Python Path:    

['/home/qliq/djenv/quoteapp',
 '/home/qliq/djenv/lib/python2.6/site-packages/distribute-0.6.10-py2.6.egg',
 '/home/qliq/djenv/lib/python2.6/site-packages/pip-0.7.2-py2.6.egg',
 '/home/qliq/djenv/lib/python2.6',
 '/home/qliq/djenv/lib/python2.6/plat-linux2',
 '/home/qliq/djenv/lib/python2.6/lib-tk',
 '/home/qliq/djenv/lib/python2.6/lib-old',
 '/home/qliq/djenv/lib/python2.6/lib-dynload',
 '/usr/lib/python2.6',
 '/usr/lib/python2.6/plat-linux2',
 '/usr/lib/python2.6/lib-tk',
 '/home/qliq/djenv/lib/python2.6/site-packages']
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感谢您的帮助以解决此问题.

Ala*_*air 36

您想要搜索作者的author_name字段,而不是ID.

Quote.objects.filter(author__author_name=name)
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对于您当前的搜索,author__exactDjango期望name成为作者的id,因此给出错误,因为you它不是整数.


U-D*_*DON 5

aquotelist = Quote.objects.filter(author__author_name__exact = name)
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尝试将相应的行更改为上述内容。你现在拥有它的方式,你匹配author给定的名称,但author可能是由它的 ID 在这里考虑的,绝对不是它的author_name. 格式如下:

Quote.objects.filter([model]__[field]__exact = [whatever])
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