在foreach循环中使用SQL结果

Ric*_*hie 4 php mysql foreach

我感觉好像在这里遗漏了一些显而易见的东西,我试图获取SQL查询的结果,然后在循环中使用它们。我感觉好像缺少了一些显而易见的东西,无论是否有注释行,我都尝试过。

<?php
$sentToID = $_SESSION['userID'];

$query = "SELECT *
          FROM messages
          WHERE sentToID = '$sentToID'";

$results = mysql_query($query);
//$userData = mysql_fetch_array($results, MYSQL_ASSOC);

foreach ($results as $result){
    $messageID = $result['messageID'];
    $sentFromID = $result['sentFromID'];
    $subject = $result['subject'];
    $body = $result['body'];
    $dateTime = $result['dateTime'];

    $query = "SELECT usertype 
              FROM user
              WHERE userID = '$sentFromID'";
    $messageResult = mysql_query($query);
    $messageData = mysql_fetch_array($messageResult, MYSQL_ASSOC);

    $usertype = $messageData['usertype'];

    $query = "SELECT * 
              FROM $usertype
              WHERE userID = '$sentFromID'";

    $messageResult = mysql_query($query);
    $messageData = mysql_fetch_array($messageResult, MYSQL_ASSOC);

    if ($usertype == "jobseeker"){
        $forname = $messageData['forename'];
        $surname = $messageData['surname'];
        echo "<div><p>" . $forename . " " . $surname . "</p>
              <p>Subject: " . $subject ."</p>
              <p>Body: " . $body . "</p></div>";
    }
    if ($usertype == "employer"){
        $forname = $messageData['forename'];
        $surname = $messageData['surname'];
        $companyName = $messageData['companyName'];

        echo "<div><p>" . $forename . " " . $surname . " - " . $companyName . "</p>
              <p>Subject: " . $subject ."</p>
              <p>Body: " . $body . "</p></div>";
    }
}
?>
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任何帮助将不胜感激

Mic*_*ski 5

您必须首先将结果提取到数组中。看来您已开始执行此操作,但已将其注释掉。

$results = mysql_query($query);
//$userData = mysql_fetch_array($results, MYSQL_ASSOC);

$resultset = array();
while ($row = mysql_fetch_array($results)) {
  $resultset[] = $row;
}

// $resultset now holds all rows from the first query.
foreach ($resultset as $result){
 //... etc...
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Cro*_*tab 5

而不是您foreach(),您应该执行以下操作(有关更多信息,请参见mysql_query()手册页):

while($result = mysql_fetch_assoc($results)) {
    // your code
}
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