TK.*_*TK. 633 .net c# linq list
假设我有LINQ查询,例如:
var authors = from x in authorsList
where x.firstname == "Bob"
select x;
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鉴于它authorsList是类型List<Author>,我如何删除查询返回的Author元素?authorsListauthors
或者换句话说,如何删除所有名字等于Bob的名字authorsList?
注意:这是用于问题目的的简化示例.
Jon*_*eet 1087
好吧,首先要排除它们会更容易:
authorsList = authorsList.Where(x => x.FirstName != "Bob").ToList();
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但是,这只会改变值,authorsList而不是从前一个集合中删除作者.或者,您可以使用RemoveAll:
authorsList.RemoveAll(x => x.FirstName == "Bob");
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如果你真的需要基于另一个集合来做,我会使用HashSet,RemoveAll和Contains:
var setToRemove = new HashSet<Author>(authors);
authorsList.RemoveAll(x => setToRemove.Contains(x));
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Ree*_*sey 130
最好使用List <T> .RemoveAll来完成此任务.
authorsList.RemoveAll((x) => x.firstname == "Bob");
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Blu*_*ppy 46
如果你真的需要删除项目,那么Except()呢?
您可以根据新列表删除,也可以通过嵌套Linq来即时删除.
var authorsList = new List<Author>()
{
new Author{ Firstname = "Bob", Lastname = "Smith" },
new Author{ Firstname = "Fred", Lastname = "Jones" },
new Author{ Firstname = "Brian", Lastname = "Brains" },
new Author{ Firstname = "Billy", Lastname = "TheKid" }
};
var authors = authorsList.Where(a => a.Firstname == "Bob");
authorsList = authorsList.Except(authors).ToList();
authorsList = authorsList.Except(authorsList.Where(a=>a.Firstname=="Billy")).ToList();
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Dan*_*ner 29
您无法使用标准LINQ运算符执行此操作,因为LINQ提供查询,而不是更新支持.
但是您可以生成一个新列表并替换旧列表.
var authorsList = GetAuthorList();
authorsList = authorsList.Where(a => a.FirstName != "Bob").ToList();
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或者您可以authors在第二次传递中删除所有项目.
var authorsList = GetAuthorList();
var authors = authorsList.Where(a => a.FirstName == "Bob").ToList();
foreach (var author in authors)
{
authorList.Remove(author);
}
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Cod*_*ker 20
简单方案:
static void Main()
{
List<string> myList = new List<string> { "Jason", "Bob", "Frank", "Bob" };
myList.RemoveAll(x => x == "Bob");
foreach (string s in myList)
{
//
}
}
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小智 19
我在游荡,如果RemoveAll和Except以及使用HashSet的优点之间有任何区别,那么我已经做了快速的性能检查:)
using System;
using System.Collections.Generic;
using System.Diagnostics;
using System.Linq;
using System.Text;
namespace ListRemoveTest
{
class Program
{
private static Random random = new Random( (int)DateTime.Now.Ticks );
static void Main( string[] args )
{
Console.WriteLine( "Be patient, generating data..." );
List<string> list = new List<string>();
List<string> toRemove = new List<string>();
for( int x=0; x < 1000000; x++ )
{
string randString = RandomString( random.Next( 100 ) );
list.Add( randString );
if( random.Next( 1000 ) == 0 )
toRemove.Insert( 0, randString );
}
List<string> l1 = new List<string>( list );
List<string> l2 = new List<string>( list );
List<string> l3 = new List<string>( list );
List<string> l4 = new List<string>( list );
Console.WriteLine( "Be patient, testing..." );
Stopwatch sw1 = Stopwatch.StartNew();
l1.RemoveAll( toRemove.Contains );
sw1.Stop();
Stopwatch sw2 = Stopwatch.StartNew();
l2.RemoveAll( new HashSet<string>( toRemove ).Contains );
sw2.Stop();
Stopwatch sw3 = Stopwatch.StartNew();
l3 = l3.Except( toRemove ).ToList();
sw3.Stop();
Stopwatch sw4 = Stopwatch.StartNew();
l4 = l4.Except( new HashSet<string>( toRemove ) ).ToList();
sw3.Stop();
Console.WriteLine( "L1.Len = {0}, Time taken: {1}ms", l1.Count, sw1.Elapsed.TotalMilliseconds );
Console.WriteLine( "L2.Len = {0}, Time taken: {1}ms", l1.Count, sw2.Elapsed.TotalMilliseconds );
Console.WriteLine( "L3.Len = {0}, Time taken: {1}ms", l1.Count, sw3.Elapsed.TotalMilliseconds );
Console.WriteLine( "L4.Len = {0}, Time taken: {1}ms", l1.Count, sw3.Elapsed.TotalMilliseconds );
Console.ReadKey();
}
private static string RandomString( int size )
{
StringBuilder builder = new StringBuilder();
char ch;
for( int i = 0; i < size; i++ )
{
ch = Convert.ToChar( Convert.ToInt32( Math.Floor( 26 * random.NextDouble() + 65 ) ) );
builder.Append( ch );
}
return builder.ToString();
}
}
}
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结果如下:
Be patient, generating data...
Be patient, testing...
L1.Len = 985263, Time taken: 13411.8648ms
L2.Len = 985263, Time taken: 76.4042ms
L3.Len = 985263, Time taken: 340.6933ms
L4.Len = 985263, Time taken: 340.6933ms
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我们可以看到,在这种情况下最好的选择是使用RemoveAll(HashSet)
这是一个非常古老的问题,但我发现了一个非常简单的方法:
authorsList = authorsList.Except(authors).ToList();
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请注意,由于返回变量authorsList是a List<T>,因此IEnumerable<T>返回的Except()必须转换为a List<T>.
您可以通过两种方式删除
var output = from x in authorsList
where x.firstname != "Bob"
select x;
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要么
var authors = from x in authorsList
where x.firstname == "Bob"
select x;
var output = from x in authorsList
where !authors.Contains(x)
select x;
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我有同样的问题,如果你想根据你的条件得到简单的输出,那么第一个解决方案就更好了.
说authorsToRemove是一个IEnumerable<T>包含您要移除的元素authorsList.
然后,这是完成OP提出的删除任务的另一种非常简单的方法:
authorsList.RemoveAll(authorsToRemove.Contains);
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下面是从列表中删除元素的示例。
List<int> items = new List<int>() { 2, 2, 3, 4, 2, 7, 3,3,3};
var result = items.Remove(2);//Remove the first ocurence of matched elements and returns boolean value
var result1 = items.RemoveAll(lst => lst == 3);// Remove all the matched elements and returns count of removed element
items.RemoveAt(3);//Removes the elements at the specified index
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我想你可以做这样的事情
authorsList = (from a in authorsList
where !authors.Contains(a)
select a).ToList();
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虽然我认为已经给出的解决方案以更易读的方式解决了问题.
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