Raf*_*fee 3 javascript jquery function
<script type="text/javascript" src="jscripts/jquery.js"></script>
<script type="text/javascript">
$(document).ready(function(){
alert("funciton");
$(function(){
$.fn.gotof(){
alert("I am calling form jquery");
}
});
});
</script>
<input type="button" onclick="dofunc();">
<script type="text/javascript">
function dofunc(){
gotof();
}
</script>
Run Code Online (Sandbox Code Playgroud)
我如何调用gotof()jquery中存在的内容,以下是在jsfiddle上编写的代码
您的代码中存在一些错误.修正了它应该是这样的:
$.fn.gotof = function() { // has to be defined as a function, does not need to be inside a nested document ready function
alert("I am calling form jquery");
};
$(document).ready(function() {
alert("function is ready to use now");
});
function dofunc() {
$.fn.gotof(); // can call it using $.fn.gotof(), but it should really be called properly via a selector $('div').gotof();
}
Run Code Online (Sandbox Code Playgroud)