Nik*_*k88 9 android web-services ksoap
如果我试图检索第一个数组, (String) response.getProperty(0);但它返回一个完整的字符串.
**Here is the code of webservice calling**
public static Object getResponse(String methodName, String actionName, LinkedHashMap<String, String> valueStrings)
{
SoapObject soapObject = new SoapObject(LetUsClickAPIConstants.COMMON_NAMESPACE, methodName);
Object response = null;
for (Map.Entry<String, String> mapKeys : valueStrings.entrySet())
{
soapObject.addProperty(mapKeys.getKey(), mapKeys.getValue());
}
final SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
envelope.dotNet = false;
envelope.setOutputSoapObject(soapObject);
final AndroidHttpTransport androidHttpTransport = new AndroidHttpTransport(LetUsClickAPIConstants.COMMON_URL);
try
{
androidHttpTransport.call(actionName, envelope);
response = envelope.getResponse();
Log.d("Response ", response.toString());
} catch (final IOException e)
{
Log.d("Exception", "" + e);
} catch (final XmlPullParserException e)
{
Log.d("Exception", "" + e);
}
return response;
}
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我在Vector类型中得到了回复
[Client{UserId=93; nickName=ladies; }, Client{UserId=94; nickName=ABCD; }]
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我尝试了很多方法但是我不能以任何方式检索成功吗?
使用以下代码..
Soapresponse = Ksoap.CallService("SOAP_METHOD_NAME);
try {
if (Soapresponse != null) {
SoapObject Soapresult = (SoapObject) Soapresponse
.getProperty(0);
if (Soapresult != null) {
SoapObject Dataset = (SoapObject) Soapresult
.getProperty(1);
if (Dataset != null) {
SoapObject Table = (SoapObject) Dataset
.getProperty(0);
if (Table != null) {
UserId= new String[Table.getPropertyCount()];
nickName= new String[Table
.getPropertyCount()];
for (int i = 0; i < total_News; i++) {
SoapObject row = (SoapObject) Table
.getProperty(i);
UserId[i] = row.getProperty("UserId")
.toString();
nickName[i] = row.getProperty(
"nickName").toString();
}
}
}
}
}
} catch (NullPointerException f) {
} catch (ClassCastException d) {
}
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