eJm*_*eJm 1 java objective-c instantiation
我有一个关于在一个方法中作为参数传递的类中实例化java中的新对象的查询,例如:
void myMethod(Class aReceived){
object = new aReceived // object will be a superclass of aReceived
}
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我已经看到使用Objective-C在几行中完成了这一点,但我不确定它在java中是如何工作的.
你能帮我吗?
提前致谢 ;)
如果要通过no-arg构造函数创建对象:
void myMethod(Class<?> aReceived) {
Object newObject = aReceived.newInstance();
...
}
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如果要通过双arg构造函数创建对象(使用String,int):
void myMethod(Class<?> aReceived) {
Object newObject = aReceived.getConstructor(String.class, int.class)
.newInstance("aaa", 222);
...
}
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最后,您可以使用泛型来正确设置newObject变量的类型(在上述任一片段的顶部):
void myMethod(Class<T> aReceived) {
T newObject = aReceived.getConstructor(String.class, int.class)
.newInstance("aaa", 222);
...
// Sadly, due to erasure of generics you cannot do newObject.SomeMethodOfT()
// because T is effectively erased to Object. You can only invoke the
// methods of Object and/or use refelection to dynamically manipulate newObject
}
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[附录]
你怎么称呼这种方法?
选项1 - 当你知道,在代码编写时,你想要传递给方法的类:
myMethod(TestClass.class)
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选项2 - 当要实例化的类的名称仅在运行时知道时,作为字符串:
String className = ....; // Name of class to be instantiated
myMethod(Class.forName(className));
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