从字符串中替换非ASCII字符

Question

我有一个字符串 A função,Ãugent在我需要更换字符像ç,ã,Ã空字符串.

如何只匹配那些非ASCII字符？

我正在使用一个功能

public static String matchAndReplaceNonEnglishChar(String tmpsrcdta)
    {
        String newsrcdta = null;
        char array[] = Arrays.stringToCharArray(tmpsrcdta);
        if (array == null)
            return newsrcdta;

        for (int i = 0; i < array.length; i++)
        {           
            int nVal = (int)array[i];
            boolean bISO = Character.isISOControl(array[i]); // Is character ISO control
            boolean bIgnorable = Character.isIdentifierIgnorable(array[i]); // Is Ignorable identifier
            // Remove tab and other unwanted characters..
            if (nVal == 9 || bISO || bIgnorable)
                array[i] = ' ';
            else if (nVal > 255)
                array[i] = ' ';
        }
        newsrcdta = Arrays.charArrayToString(array);

        return newsrcdta;
    }

但它没有正常工作......需要多大改进...这里我还有一个问题是最后的字符串被空格字符替换,这会在字符串中创建额外的空间.

Answer 1

这将搜索并替换所有非ASCII字母:

String resultString = subjectString.replaceAll("[^\\x00-\\x7F]", "");

Answer 2

FailedDev的答案很好,但可以改进.如果要保留ascii等效项,则需要先进行规范化:

String subjectString = "öäü";
subjectString = Normalizer.normalize(subjectString, Normalizer.Form.NFD);
String resultString = subjectString.replaceAll("[^\\x00-\\x7F]", "");

=> will produce "oau"

这样,像"öäü"这样的字符将被映射到"oau",这至少会保留一些信息.如果没有规范化,生成的String将为空.

Answer 3

这将是Unicode解决方案

String s = "A função, Ãugent";
String r = s.replaceAll("\\P{InBasic_Latin}", "");

\p{InBasic_Latin}是一个包含以Unicode范围内的所有字母的Unicode块U + 0000..U + 007F(参照regular-expression.info)

\P{InBasic_Latin} 被否定了 \p{InBasic_Latin}