我使用OleDb从Excel文件中获取无效的工作表名称.怎么了?

dda*_*lis 5 c# oledb

我试着用oledb获得excel表名.

我的连接字符串是:

"Provider=Microsoft.ACE.OLEDB.12.0;Data Source=" +
filepath + 
";Extended Properties=Excel 12.0;";
Run Code Online (Sandbox Code Playgroud)

filepath文件名在哪里.

我的代码:

List<string> sheetNames = new List<string>();
_excel.Connect(_path);
DataTable dataTable = _excel.ExecuteSchema();
_excel.Disconnect();
foreach (DataRow row in dataTable.Rows)
{
    string sheetName = row["TABLE_NAME"].ToString();
    if(!sheetName.EndsWith("$'")) { continue; }
    sheetNames.Add(sheetName);
 }
Run Code Online (Sandbox Code Playgroud)

带有工作表名称的列表包含所有有效的工作表名称和一些其他工作表名称.例:

  • "'correctsheetname$'"
  • "'correctsheetname$'Print_Area"

我只添加了最后的表格 $'

我的问题是,如果工作表名称包含单引号,我会使用两个单引号.

示例:对于名为asheetname'sI get的工作表'asheetname''s$''

之后,当我尝试获取此工作表的数据源时,我得到一个例外,即此工作表不存在.

query = "SELECT * FROM ['asheetname''s$']"
_command = new OleDbCommand(query, _connection);
_dataTable = new DataTable();
_dataReader = _command.ExecuteReader();   <-- Exception is thrown here
Run Code Online (Sandbox Code Playgroud)

并且异常消息:

{System.Data.OleDb.OleDbException: ''asheetname''s$'' is not a valid name. Make sure that it does not include invalid characters or punctuation and that it is not too long. at System.Data.OleDb.OleDbCommand.ExecuteCommandTextErrorHandling(OleDbHResult hr) at System.Data.OleDb.OleDbCommand.ExecuteCommandTextForSingleResult(tagDBPARAMS dbParams, Object& executeResult) at System.Data.OleDb.OleDbCommand.ExecuteCommandText(Object& executeResult) at System.Data.OleDb.OleDbCommand.ExecuteCommand(CommandBehavior behavior, Object& executeResult) at System.Data.OleDb.OleDbCommand.ExecuteReaderInternal(CommandBehavior behavior, String method) at System.Data.OleDb.OleDbCommand.ExecuteReader(CommandBehavior behavior) at System.Data.OleDb.OleDbCommand.ExecuteReader() at PrestaImporter.Entity.Excel.ExecuteQuery(String query)

And*_*rew 5

这应该工作

"SELECT * FROM [" + asheetname + "$]"
Run Code Online (Sandbox Code Playgroud)

如果不行,请尝试在字符串变量asheetname中手动输入工作表名称-应该打开。

"SELECT * FROM ["SHEET_NAME"$]"
Run Code Online (Sandbox Code Playgroud)