在clojure中,如何将列表传递给参数化函数(及更多)

Question

说我有功能:

(defn foo [something & otherthings]
  (println something)
  (println otherthings))

评估

(foo "ack" "moo" "boo")

给我 :

ack                                                               
(moo boo) 

如果我想用列表调用foo怎么办？

(foo "ack" (list "moo" "boo"))

得到

ack                                                            
(moo boo) 

代替

ack                                            
((moo boo)) 

有没有办法在不改变foo的情况下做到这一点？

Answer 1

你想要apply:

(apply foo "ack" (list "moo" "boo"))