use*_*694 4 python math trigonometry
import math
print "python calculator"
print "calc or eval"
while 0 == 0:
check = raw_input() #(experimental evaluation or traditional calculator)
if check == "eval":
a = raw_input("operator\n") #operator
if a == "+":
b = input("arg1\n") #inarg1
c = input("arg2\n") #inarg2
z = b + c
print z
elif a == "-":
b = input("arg1\n") #inarg1
c = input("arg2") #inarg2
z = b - c
print z
elif a == "/":
b = input("arg1\n") #inarg1
c = input("arg2\n") #inarg2
z = b / c
print z
elif a == "*":
b = input("arg1\n") #inarg1
c = input("arg2]n") #inarg2
z = b * c
print z
elif a == "^":
b = input("arg1\n") #inarg1
c = input("arg2\n") #inarg2
z = b ** c
elif a == "sin":
b = input("arg1\n") #inarg1
var = math.degrees(math.sin(b))
print var
elif a == "asin":
b = input("arg1\n") #inarg1
var = math.degrees(math.asin(b))
print var
elif a == "cos":
b = input("arg1\n") #inarg1
var = math.degrees(math.cos(b))
print var
elif a == "acos":
b = input("arg1\n") #inarg1
var = math.degrees(math.acos(b))
print var
elif a == "tan":
b = input("arg1\n") #inarg1
var = math.degrees(math.tan(b))
print var
elif a == "atan":
b = input("arg1\n") #inarg1
var = math.degrees(math.atan(b))
print var
elif check == "calc" :
x = input() #takes input as expression
print x #prints expression's result
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不是90度1的正弦?有了它,它显示为51.2左右的东西?Google的计算器也是这样做的吗?顺便说一句:这是我的python计算器
b = input("arg1\n") #inarg1
var = math.degrees(math.sin(b))
print var
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这个和其他触发功能是问题所在.在大多数情况下,这只是一个简单的python计算器,但我想添加一些trig函数.
Sve*_*ach 10
您不希望将返回值转换sin()
为度数 - 返回值不是角度.你想要将参数转换为弧度,因为math.sin()
需要弧度:
>>> math.sin(math.radians(90))
1.0
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