Ric*_*hie 4 php mysql foreach search explode
我正在努力创建一个搜索多个单词的搜索.我的第一次尝试没有取得任何结果,如下:
require_once('database_conn.php');
if($_POST){
$explodedSearch = explode (" ", $_POST['quickSearch']);
foreach($explodedSearch as $search){
$query = "SELECT *
FROM jobseeker
WHERE forename like '%$search%' or surname like '%$search%'
ORDER BY userID
LIMIT 5";
$result = mysql_query($query);
}
while($userData=mysql_fetch_array($result)){
$forename=$userData['forename'];
$surname=$userData['surname'];
$profPic=$userData['profilePicture'];
$location=$userData['location'];
echo "<div class=\"result\">
<img class=\"quickImage\" src=\"" . $profPic. "\" width=\"45\" height=\"45\"/>
<p class=\"quickName\">" . $forename . " " . $surname . "</p>
<p class=\"quickLocation\"> " . $location . "</p>
</div>";
}
}
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我也尝试了下面的结果,但是你可以想象,我输入的每个单词的结果都是重复的:
if($_POST){
$explodedSearch = explode (" ", $_POST['quickSearch']);
foreach($explodedSearch as $search){
$query = "SELECT *
FROM jobseeker
WHERE forename like '%$search%' or surname like '%$search%'
ORDER BY userID
LIMIT 5";
$result .= mysql_query($query);
while($userData=mysql_fetch_array($result)){
$forename=$userData['forename'];
$surname=$userData['surname'];
$profPic=$userData['profilePicture'];
$location=$userData['location'];
echo "<div class=\"result\">
<img class=\"quickImage\" src=\"" . $profPic. "\" width=\"45\" height=\"45\"/>
<p class=\"quickName\">" . $forename . " " . $surname . "</p>
<p class=\"quickLocation\"> " . $location . "</p>
</div>";
}
}
}
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我对如何继续这一点感到很遗憾,任何帮助都将不胜感激.
编辑:
if($_POST){
$quickSearch = $_POST['quickSearch'];
$explodedSearch = explode (" ", trim($quickSearch));
$queryArray = array();
foreach($explodedSearch as $search){
$term = mysql_real_escape_string($search);
$queryArray[] = "forename like '%" . $term . "%' surname like '%" . $term . "%'";
}
$implodedSearch = implode(' or ', $queryArray);
$query="SELECT *
FROM jobseeker
WHERE ($implodedSearch)
ORDER BY userID
LIMIT 5";
$result = mysql_query($query);
while($userData=mysql_fetch_array($result, MYSQL_ASSOC)){
$forename=$userData['forename'];
$surname=$userData['surname'];
$profPic=$userData['profilePicture'];
$location=$userData['location'];
echo "<div class=\"result\">
<img class=\"quickImage\" src=\"" . $profPic. "\" width=\"45\" height=\"45\"/>
<p class=\"quickName\">" . $forename . " " . $surname . "</p>
<p class=\"quickLocation\"> " . $location . "</p>
</div>";
}
}
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Med*_*m Z 10
我一直在研究相同的主题(用关键字搜索)一段时间,这是我做到的:
$words = $_POST['keywords'];
if(empty($words)){
//redirect somewhere else!
}
$parts = explode(" ",trim($words));
$clauses=array();
foreach ($parts as $part){
//function_description in my case , replace it with whatever u want in ur table
$clauses[]="function_description LIKE '%" . mysql_real_escape_string($part) . "%'";
}
$clause=implode(' OR ' ,$clauses);
//select your condition and add "AND ($clauses)" .
$sql="SELECT *
FROM functions
WHERE
user_name='{$user_name}'
AND ($clause) ";
$results=mysql_query($sql,$connection);
if(!$results){
redirect("errors/error_db.html");
}
else if($results){
$rows = array();
<?php
while($rows = mysql_fetch_array($results, MYSQL_ASSOC))
{
// echo whatever u want !
}
?>
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- 现在这是我尝试使用FULLTEXT搜索运行时的样子:但是你应该将表类型设置为"MyISAM"
<?php
$words = mysql_real_escape_string($_POST['function_keywords']);
if(empty($words)){
redirect("welcome.php?error=search_empty");
}
//if the columns(results)>1/2(columns) => it will return nothing!(use "NATURAL LANGUAGE"="BOOLEAN")
$sql="SELECT * FROM functions
WHERE MATCH (function_description)
AGAINST ('{$words}' IN NATURAL LANGUAGE MODE)";
$results=mysql_query($sql,$connection);
if(!$results){
redirect("errors/error_db.html");
}
else if($results){
$rows = array();
while($rows = mysql_fetch_array($results, MYSQL_ASSOC))
{
// echo
}
}
?>
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