使用Jackson JSON Views而不注释原始bean类

Question

有没有什么方法可以使用Jackson JSON Views或类似的东西,而无需注释原始的bean类？我正在寻找某种运行时/动态配置让我做类似的事情.

我的bean是@Entity一个JAR打包的,可以由多个项目共享.我正试图避免因为消费项目中的UI更改而触摸并重新打包共享JAR.

理想情况下,我想做点什么

jsonViewBuilder = createViewBuilder(View.class);
jsonViewBuilder.addProperty("property1");
jsonViewBuilder.addProperty("property2");

取代

Bean {
  @JsonView(View.class)
  String property1;

  @JsonView(View.class)
  String property2;
}

有任何想法吗？

底层环境:Spring 3.0,Spring MVC和Glassfish 3.1.1.

Answer 1

如何使用Mix-In功能？

http://wiki.fasterxml.com/JacksonMixInAnnotations

http://www.cowtowncoder.com/blog/archives/2009/08/entry_305.html

import org.codehaus.jackson.annotate.JsonAutoDetect.Visibility;
import org.codehaus.jackson.annotate.JsonMethod;
import org.codehaus.jackson.map.ObjectMapper;
import org.codehaus.jackson.map.SerializationConfig;
import org.codehaus.jackson.map.annotate.JsonView;

public class JacksonFoo
{
  public static void main(String[] args) throws Exception
  {
    ObjectMapper mapper = new ObjectMapper().setVisibility(JsonMethod.FIELD, Visibility.ANY)
        .configure(SerializationConfig.Feature.DEFAULT_VIEW_INCLUSION, false);
    mapper.getSerializationConfig().addMixInAnnotations(Bar.class, BarMixIn.class);
    mapper.setSerializationConfig(mapper.getSerializationConfig().withView(Expose.class));

    System.out.println(mapper.writeValueAsString(new Bar()));
    // output: {"b":"B"}
  }
}

class Bar
{
  String a = "A";
  String b = "B";
}

abstract class BarMixIn
{
  @JsonView(Expose.class)
  String b;
}

// Used only as JsonView marker.  
// Could use any existing class, like Object, instead.  
class Expose {}