Sha*_*arr 10 c sockets linux networking tcp
我有一个应用程序从服务器读取大文件并经常挂起在特定的机器上.它已在RHEL5.2下成功运行了很长时间.我们最近升级到RHEL6.1,它现在定期挂起.
我创建了一个可以重现问题的测试应用程序.它在100个中挂起约98次.
#include <errno.h>
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <sys/param.h>
#include <sys/stat.h>
#include <sys/types.h>
#include <unistd.h>
#include <netdb.h>
#include <sys/socket.h>
#include <sys/time.h>
int mFD = 0;
void open_socket()
{
struct addrinfo hints, *res;
memset(&hints, 0, sizeof(hints));
hints.ai_socktype = SOCK_STREAM;
hints.ai_family = AF_INET;
if (getaddrinfo("localhost", "60000", &hints, &res) != 0)
{
fprintf(stderr, "Exit %d\n", __LINE__);
exit(1);
}
mFD = socket(res->ai_family, res->ai_socktype, res->ai_protocol);
if (mFD == -1)
{
fprintf(stderr, "Exit %d\n", __LINE__);
exit(1);
}
if (connect(mFD, res->ai_addr, res->ai_addrlen) < 0)
{
fprintf(stderr, "Exit %d\n", __LINE__);
exit(1);
}
freeaddrinfo(res);
}
void read_message(int size, void* data)
{
int bytesLeft = size;
int numRd = 0;
while (bytesLeft != 0)
{
fprintf(stderr, "reading %d bytes\n", bytesLeft);
/* Replacing MSG_WAITALL with 0 works fine */
int num = recv(mFD, data, bytesLeft, MSG_WAITALL);
if (num == 0)
{
break;
}
else if (num < 0 && errno != EINTR)
{
fprintf(stderr, "Exit %d\n", __LINE__);
exit(1);
}
else if (num > 0)
{
numRd += num;
data += num;
bytesLeft -= num;
fprintf(stderr, "read %d bytes - remaining = %d\n", num, bytesLeft);
}
}
fprintf(stderr, "read total of %d bytes\n", numRd);
}
int main(int argc, char **argv)
{
open_socket();
uint32_t raw_len = atoi(argv[1]);
char raw[raw_len];
read_message(raw_len, raw);
return 0;
}
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我测试的一些注意事项:
测试应用程序的源代码可以在这里找到:
可以在此处找到loopback接口的tcpdump捕获:
我通过发出以下命令重现该问题:
> gcc socket_test.c -o socket_test
> perl -e 'for (1..6000000){ print "a" }' | nc -l 60000
> ./socket_test 6000000
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这看到发送到测试应用程序的6000000个字节,它试图使用一次调用recv()来读取数据.
我很想听听有关我可能做错的建议或任何进一步调试问题的方法.