Moj*_*oDK 2 model-view-controller json xamarin.ios
在我的测试vb.net MVC网络应用程序中,我有这个json ....
Public Class Person
Public Property Name As String
Public Property Age As Byte
Public Sub New(name As String, age As Byte)
Me.Name = name
Me.Age = age
End Sub
End Class
Function GetPerson() As JsonResult
Dim p As New Person("John Doe", 50)
Return Json(p, JsonRequestBehavior.AllowGet)
End Function
Run Code Online (Sandbox Code Playgroud)
在Monotouch我有这个......
JsonObject j;
Uri address = new Uri("http://mysite/home/GetPerson");
HttpWebRequest httpReq = (HttpWebRequest)HttpWebRequest.Create (address);
using (HttpWebResponse httpRes = (HttpWebResponse)httpReq.GetResponse ()) {
Stream s = httpRes.GetResponseStream ();
j = (JsonObject)JsonObject.Load (s);
}
Run Code Online (Sandbox Code Playgroud)
而这堂课......
Public Class Person {
Public string Name { get; set; }
Public byte Age { get; set; }
}
Run Code Online (Sandbox Code Playgroud)
如何将JsonObject j解析为Person类?..我希望像Person p =(Person)j.value;
谢谢!魔
首先,我会使用int作为Age.但假设JSON结构如下:
{
"Name" : "John Doe",
"Age" : 100,
}
Run Code Online (Sandbox Code Playgroud)
如果你想在System.Json中使用烘焙:
var person = new Person()
var obj = JsonObject.Parse(json);
person.Name = obj["Name"].ToString();
person.Age = (int)obj["Age"];
Run Code Online (Sandbox Code Playgroud)
我强烈建议使用ServiceStack.Text,它是一个高度优化的极快库,用于消费JSON,兼容MonoTouch和Mono for Android ......开箱即用!
您可以在此处查看使用ServiceStack消费JSON的API .
| 归档时间: |
|
| 查看次数: |
2302 次 |
| 最近记录: |