我在PHP中有一个简单的查询,但我无法开始Like工作.
这是代码:
$var = $_GET['q'];
$trimmed = trim($var);
$query = "SELECT * FROM vm_regiony WHERE nazev LIKE "%$trimmed%" order by id LIMIT 10";
$result = mysql_query($query);
if(mysql_num_rows($result)==0){
echo "nothing";
echo "<br />";
echo $trimmed;
}else{
while($rene=mysql_fetch_array($result)){
$jmeno = $rene['nazev'];
echo '<a id="hled" onclick="javascript:vybrat()">'.$jmeno.'</a>';
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对于一个你需要在那里使用单引号
$query = "SELECT * FROM vm_regiony WHERE nazev LIKE '%$trimmed%' order by id LIMIT 10";
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