mar*_*zzz 76 .net c# xml parsing xml-parsing
我有这个XML(存储在一个C#字符串中myXML)
<?xml version="1.0" encoding="utf-16"?>
<myDataz xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<listS>
<sog>
<field1>123</field1>
<field2>a</field2>
<field3>b</field3>
</sog>
<sog>
<field1>456</field1>
<field2>c</field2>
<field3>d</field3>
</sog>
</listS>
</myDataz>
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我想浏览所有<sog>元素.对于他们每个人,我想打印孩子<field1>.
所以这是我的代码:
XmlDocument xmlDoc = new XmlDocument();
string myXML = "<?xml version=\"1.0\" encoding=\"utf-16\"?><myDataz xmlns:xsi=\"http://www.w3.org/2001/XMLSchema-instance\" xmlns:xsd=\"http://www.w3.org/2001/XMLSchema\"><listS><sog><field1>123</field1><field2>a</field2><field3>b</field3></sog><sog><field1>456</field1><field2>c</field2><field3>d</field3></sog></listS></myDataz>"
xmlDoc.Load(myXML);
XmlNodeList parentNode = xmlDoc.GetElementsByTagName("listS");
foreach (XmlNode childrenNode in parentNode)
{
HttpContext.Current.Response.Write(childrenNode.SelectSingleNode("//field1").Value);
}
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但似乎我无法读取字符串作为XML?我明白了System.ArgumentException
And*_*huk 98
你应该使用LoadXml方法,而不是Load:
xmlDoc.LoadXml(myXML);
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Load方法试图从文件加载xml并从字符串加载LoadXml.你也可以使用XPath:
XmlDocument xmlDoc = new XmlDocument();
xmlDoc.LoadXml(xml);
string xpath = "myDataz/listS/sog";
var nodes = xmlDoc.SelectNodes(xpath);
foreach (XmlNode childrenNode in nodes)
{
HttpContext.Current.Response.Write(childrenNode.SelectSingleNode("//field1").Value);
}
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ada*_*ost 17
使用Linq-XML,
XDocument doc = XDocument.Load(file);
var result = from ele in doc.Descendants("sog")
select new
{
field1 = (string)ele.Element("field1")
};
foreach (var t in result)
{
HttpContext.Current.Response.Write(t.field1);
}
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或者:获取<sog>标记的节点列表.
XmlDocument xmlDoc = new XmlDocument();
xmlDoc.Load(myXML);
XmlNodeList parentNode = xmlDoc.GetElementsByTagName("sog");
foreach (XmlNode childrenNode in parentNode)
{
HttpContext.Current.Response.Write(childrenNode.SelectSingleNode("field1").InnerText);
}
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sra*_*boy 10
其他答案已有几年的历史了(并且不适用于Windows Phone 8.1)所以我想我会选择其他选项.我用它来解析Windows Phone应用程序的RSS响应:
XDocument xdoc = new XDocument();
xdoc = XDocument.Parse(xml_string);
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