如何使用jQuery选择表列

Question

我想选择一个表列,我所知道的是列的标题文本.(th.innerText)

我尝试了以下代码,但它不起作用:

ownerIndex = $('th:contains("Owner")').index();
$('table tr td:nth-child(ownerIndex)')

有任何想法吗？

Answer 1

好.我找到了解决方案:

$('table tr td:nth-child('+ownerIndex+')')

Answer 2

在上面的示例中,ownerIndex需要递增1以匹配nth-child的索引,该索引从1开始而不是0.

这是我的看法:http: //jsfiddle.net/2xU8t/

/* Set all the cells in columns with THEHEADING in the heading to red */

// Find the heading with the text THEHEADING
columnTh = $("table th:contains('THEHEADING')");

// Get the index & increment by 1 to match nth-child indexing
columnIndex = columnTh.index() + 1; 

// Set all the elements with that index in a tr red
$('table tr td:nth-child(' + columnIndex + ')').css("color", "#F00");

// Set the heading red too!
columnTh.css("color", "#F00");