HTML表单数据通过PHP

Question

我对PHP脚本完全不熟悉,并将以下代码放在一起,但我希望收到的电子邮件显示它是从HTML表单中的电子邮件字段发送而不是当前的"The Tranquility Zone Website [www.tranquilityzone.co" .UK @ linweb.ahost.me]".请问你能告诉我应该改变什么.非常感谢.

<?
$msg .= "Name:\t $_POST[name]\n";
$msg .= "E-mail:\t $_POST[email]\n";
$msg .= "Telephone:\t $_POST[telephone]\n";
$msg .= "Subject:\t $_POST[subject]\n";
$msg .= "Message:\t $_POST[message]\n";

$to = "jenny@tranquilityzone.co.uk";
$subject = "Website feedback message";


$headers = 'From: '.$email_from."\r\n".
            'Reply-To: '.$email_from."\r\n" .

$mailheaders = "From: The Tranquility Zone Website <www.tranquilityzone.co.uk>\n";
$mailherders .= "Reply to: $_POST[sender_email]\n";


header( "Location: http://www.tranquilityzone.co.uk/thank_you.html" );

@mail ($to, $subject, $msg, $mailheaders);
?>

Answer 1

看起来您的第二个邮件头 (mailherders) 变量中有拼写错误

尝试这个：

$headers = 'From: '.$email_from."\r\n".
            'Reply-To: '.$email_from."\r\n" .

$mailheaders = "From: The Tranquility Zone Website <www.tranquilityzone.co.uk>\n";
$mailheaders .= "Reply-to: $_POST[sender_email]\n";

我的免责声明：我不容忍这种类型的活动，因为当您收到来自真正发件人以外的人的电子邮件时，它看起来非常可疑。是的，您可能会因此被列入黑名单。