Jea*_*Jea 7 xpath xquery xpath-2.0
我有一个包含作者和编辑器的XML文件.
<?xml version="1.0" encoding="UTF-8"?>
<?oxygen RNGSchema="file:textbook.rnc" type="compact"?>
<books xmlns="books">
<book ISBN="i0321165810" publishername="OReilly">
<title>XPath</title>
<author>
<name>
<fname>Priscilla</fname>
<lname>Walmsley</lname>
</name>
</author>
<year>2007</year>
<field>Databases</field>
</book>
<book ISBN="i0321165812" publishername="OReilly">
<title>XQuery</title>
<author>
<name>
<fname>Priscilla</fname>
<lname>Walmsley</lname>
</name>
</author>
<editor>
<name>
<fname>Lisa</fname>
<lname>Williams</lname>
</name>
</editor>
<year>2003</year>
<field>Databases</field>
</book>
<publisher publishername="OReilly">
<web-site>www.oreilly.com</web-site>
<address>
<street_address>hill park</street_address>
<zip>90210</zip>
<state>california</state>
</address>
<phone>400400400</phone>
<e-mail>oreilly@oreilly.com</e-mail>
<contact>
<field>Databases</field>
<name>
<fname>Anna</fname>
<lname>Smith</lname>
</name>
</contact>
</publisher>
</books>
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我正在寻找一种方法来返回作为作者和/或编辑被列出次数最多的人.解决方案应该是XQuery 1.0(XPath 2.0)兼容.
我正在考虑使用FLWOR查询迭代所有作者和编辑,然后计算唯一的作者/编辑,然后返回匹配最高计数的作者/编辑.但我一直无法找到合适的解决方案.
有没有人对如何写这样的FLWOR查询有任何建议?可以使用XPath以更简单的方式完成吗?
最好的祝福,
珍妮特
Chr*_*rün 16
这可能有所帮助:
declare default element namespace 'books';
(for $name in distinct-values($doc/books/*/*/name)
let $entries := $doc/books/*[data(*/name) = $name]
order by count($entries) descending
return $entries/*/name)[1]
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这是一个纯粹的XPath 2.0表达式,诚然不适合胆小的人:
(for $m in max(for $n in distinct-values(/*/b:book/(b:author | b:editor)
/b:name/concat(b:fname, '|', b:lname)),
$cnt in count(/*/b:book/(b:author | b:editor)
/b:name[$n eq concat(b:fname, '|', b:lname) ])
return $cnt
),
$name in /*/b:book/(b:author | b:editor)/b:name,
$fullName in $name/concat(b:fname, '|', b:lname),
$count in count( /*/b:book/(b:author | b:editor)
/b:name[$fullName eq concat(b:fname, '|', b:lname)])
return
if($count eq $m)
then $name
else ()
)[1]
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前缀"b:"与命名空间相关联的位置"books".
基于XSLT 2.0的验证:
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:b="books">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="/">
<xsl:sequence select=
"(for $m in max(for $n in distinct-values(/*/b:book/(b:author | b:editor)
/b:name/concat(b:fname, '|', b:lname)),
$cnt in count(/*/b:book/(b:author | b:editor)
/b:name[$n eq concat(b:fname, '|', b:lname) ])
return $cnt
),
$name in /*/b:book/(b:author | b:editor)/b:name,
$fullName in $name/concat(b:fname, '|', b:lname),
$count in count( /*/b:book/(b:author | b:editor)
/b:name[$fullName eq concat(b:fname, '|', b:lname)])
return
if($count eq $m)
then $name
else ()
)[1]
"/>
</xsl:template>
</xsl:stylesheet>
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当此转换应用于提供的XML文档时:
<books xmlns="books">
<book ISBN="i0321165810" publishername="OReilly">
<title>XPath</title>
<author>
<name>
<fname>Priscilla</fname>
<lname>Walmsley</lname>
</name>
</author>
<year>2007</year>
<field>Databases</field>
</book>
<book ISBN="i0321165812" publishername="OReilly">
<title>XQuery</title>
<author>
<name>
<fname>Priscilla</fname>
<lname>Walmsley</lname>
</name>
</author>
<editor>
<name>
<fname>Lisa</fname>
<lname>Williams</lname>
</name>
</editor>
<year>2003</year>
<field>Databases</field>
</book>
<publisher publishername="OReilly">
<web-site>www.oreilly.com</web-site>
<address>
<street_address>hill park</street_address>
<zip>90210</zip>
<state>california</state>
</address>
<phone>400400400</phone>
<e-mail>oreilly@oreilly.com</e-mail>
<contact>
<field>Databases</field>
<name>
<fname>Anna</fname>
<lname>Smith</lname>
</name>
</contact>
</publisher>
</books>
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name选择并输出所需的正确元素:
<name xmlns="books">
<fname>Priscilla</fname>
<lname>Walmsley</lname>
</name>
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