Rob*_*Day 18 c# xml linq-to-xml xnamespace
我需要创建以下XML,我正在尝试使用XDocument.但是,我在指定名称空间时遇到了麻烦.
<AssessmentOrderRequest
xsi:schemaLocation="http://ns.hr-xml.org/2007-04-15 http://ns.hr-xml.org/2_5/HR-XML-2_5/StandAlone/AssessmentOrderRequest.xsd"
xmlns="http://ns.hr-xml.org/2007-04-15"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
</AssessmentOrderRequest>
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这是我正在寻找的那种代码,但是,我无法在名称中创建带冒号的属性xsi:schemaLocation
.
return new XDocument(
new XElement("AssessmentOrderRequest",
new XAttribute("xsi:schemaLocation", XNamespace.Get("http://ns.hr-xml.org/2007-04-15 http://ns.hr-xml.org/2_5/HR-XML-2_5/StandAlone/AssessmentOrderRequest.xsd")),
new XAttribute("xmlns", XNamespace.Get("http://ns.hr-xml.org/2007-04-15")),
new XAttribute(XNamespace.Xmlns + "xsi", XNamespace.Get("http://www.w3.org/2001/XMLSchema-instance"))
)
);
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Jam*_*mes 45
这是因为xsi
它本身就是命名空间.您需要执行以下操作:
XNamespace xmlns = XNamespace.Get("http://ns.hr-xml.org/2007-04-15");
XNamespace xsi = XNamespace.Get("http://www.w3.org/2001/XMLSchema-instance");
XNamespace schemaLocation = XNamespace.Get("http://ns.hr-xml.org/2007-04-15 http://ns.hr-xml.org/2_5/HR-XML-2_5/StandAlone/AssessmentOrderRequest.xsd");
return new XDocument(
new XElement(xmlns + "AssessmentOrderRequest",
new XAttribute(XNamespace.Xmlns + "xsi", xsi),
new XAttribute(xsi + "schemaLocation", schemaLocation)
)
);
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编辑:更新了我用来解决问题的最终代码.感谢詹姆斯的原始答案.