相对路径,但对于港口？

Question

我们都熟悉相对路径:./images/hello.jpg从http://www.domain.com/hey链接到的相对路径http://www.domain.com/hey/images/hello.jpg.

问题:你如何说明你到达http://www.domain.com:1234时的相对路径http://www.domain.com/hey？

Answer 1

这可以通过设置window.location.port属性使用JavaScript来实现.

<a href="#" onclick="javascript:window.location.port=8080">go</a>

Answer 2

您不能在相对URL中更改权限的任何部分(即主机:端口部分).见中描述的算法部分5.2.2的RFC 3986,看相对URL如何解释.需要注意的重要一点是,只需从基本URL或正在解析的URL复制权限,永远不会解释权限的结构.这意味着您无法更改其任何部件,包括端口部件.

这是从RFC复制的伪代码中的算法:

  -- The URI reference is parsed into the five URI components
  --
  (R.scheme, R.authority, R.path, R.query, R.fragment) = parse(R);

  -- A non-strict parser may ignore a scheme in the reference
  -- if it is identical to the base URI's scheme.
  --
  if ((not strict) and (R.scheme == Base.scheme)) then
     undefine(R.scheme);
  endif;

  if defined(R.scheme) then
     T.scheme    = R.scheme;
     T.authority = R.authority;
     T.path      = remove_dot_segments(R.path);
     T.query     = R.query;
  else
     if defined(R.authority) then
        T.authority = R.authority;
        T.path      = remove_dot_segments(R.path);
        T.query     = R.query;
     else
        if (R.path == "") then
           T.path = Base.path;
           if defined(R.query) then
              T.query = R.query;
           else
              T.query = Base.query;
           endif;
        else
           if (R.path starts-with "/") then
              T.path = remove_dot_segments(R.path);
           else
              T.path = merge(Base.path, R.path);
              T.path = remove_dot_segments(T.path);
           endif;
           T.query = R.query;
        endif;
        T.authority = Base.authority;
     endif;
     T.scheme = Base.scheme;
  endif;

  T.fragment = R.fragment;