Adr*_*ore 2 c# linq linq-to-entities
我在很长一段时间内获得了最奇怪的调试体验.承认这有点令人尴尬,但它让我相信我的Linq查询在添加额外的Where子句时会产生更多结果.
我知道这是不可能的,所以我重构了我的违规功能加上属于它的单元测试:
[Test]
public void LoadUserBySearchString()
{
//Setup
var AllUsers = new List<User>
{
new User
{
FirstName = "Luke",
LastName = "Skywalker",
Email = "luke@jedinet.org"
},
new User
{
FirstName = "Leia",
LastName = "Skywalker",
Email = "faeryprincess@winxmail.com"
}
};
//Execution
List<User> SearchResults = LoadUserBySearchString("princess", AllUsers.AsQueryable());
List<User> SearchResults2 = LoadUserBySearchString("princess Skywalker", AllUsers.AsQueryable());
//Assertion
Assert.AreEqual(1, SearchResults.Count); //test passed!
Assert.AreEqual(1, SearchResults2.Count); //test failed! got 2 instead of 1 User???
}
//search CustID, fname, lname, email for substring(s)
public List<User> LoadUserBySearchString(string SearchString, IQueryable<User> AllUsers)
{
IQueryable<User> Result = AllUsers;
//split into substrings and apply each substring as additional search criterium
foreach (string SubString in Regex.Split(SearchString, " "))
{
int SubStringAsInteger = -1;
if (SubString.IsInteger())
{
SubStringAsInteger = Convert.ToInt32(SubString);
}
if (SubString != null && SubString.Length > 0)
{
Result = Result.Where(c => (c.FirstName.Contains(SubString)
|| c.LastName.Contains(SubString)
|| c.Email.Contains(SubString)
|| (c.ID == SubStringAsInteger)
));
}
}
return Result.ToList();
}
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我调试了LoadUserBySearchString函数并断言第二次调用函数实际上产生了一个带有两个where子句而不是一个的linq查询.所以似乎额外的where子句增加了结果的数量.
更奇怪的是,当我手工测试它时(与来自数据库的真实用户),LoadUserBySearchString函数非常有用.它只显示运行单元测试时的这种奇怪行为.
我想我只需要一些睡眠(甚至是长假).如果有人能帮我解释一下,我可以不再质疑我的理智并重新开始工作.
谢谢,
阿德里安
编辑(澄清我到目前为止的几个回复):我知道它看起来像是条款,但不幸的是它并不那么简单.LoadUserBySearchString将搜索字符串拆分为多个字符串,并为每个字符串附加Where子句."天行者"与卢克和莱娅相匹配,但"公主"只与莱娅相匹配.
这是搜索字符串"princess"的Linq查询:
+ Result {System.Collections.Generic.List`1[TestProject.Models.User].Where(c => (((c.FirstName.Contains(value(TestProject.Controllers.SearchController+<>c__DisplayClass1).SubString) || c.LastName.Contains(value(TestProject.Controllers.SearchController+<>c__DisplayClass1).SubString)) || c.Email.Contains(value(TestProject.Controllers.SearchController+<>c__DisplayClass1).SubString)) || (c.ID = value(TestProject.Controllers.SearchController+<>c__DisplayClass3).SubStringAsInteger)))} System.Linq.IQueryable<TestProject.Models.User> {System.Linq.EnumerableQuery<TestProject.Models.User>}
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这是搜索字符串"公主天行者"的Linq条款
+ Result {System.Collections.Generic.List`1[TestProject.Models.User].Where(c => (((c.FirstName.Contains(value(TestProject.Controllers.SearchController+<>c__DisplayClass1).SubString) || c.LastName.Contains(value(TestProject.Controllers.SearchController+<>c__DisplayClass1).SubString)) || c.Email.Contains(value(TestProject.Controllers.SearchController+<>c__DisplayClass1).SubString)) || (c.ID = value(TestProject.Controllers.SearchController+<>c__DisplayClass3).SubStringAsInteger))).Where(c => (((c.FirstName.Contains(value(TestProject.Controllers.SearchController+<>c__DisplayClass1).SubString) || c.LastName.Contains(value(TestProject.Controllers.SearchController+<>c__DisplayClass1).SubString)) || c.Email.Contains(value(TestProject.Controllers.SearchController+<>c__DisplayClass1).SubString)) || (c.ID = value(TestProject.Controllers.SearchController+<>c__DisplayClass3).SubStringAsInteger)))} System.Linq.IQueryable<TestProject.Models.User> {System.Linq.EnumerableQuery<TestProject.Models.User>}
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与上面相同,只需添加一个where子句.
这是一个不错的小问题.
发生的事情是,由于匿名方法和延迟执行,你实际上并没有过滤"公主".相反,您正在构建一个过滤器,用于过滤subString变量的内容.
但是,然后您更改此变量,并构建另一个过滤器,该过滤器再次使用相同的变量.
基本上,这是您将以简短形式执行的内容:
Where(...contains(SubString)).Where(...contains(SubString))
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所以,你实际上只是对两个中存在的最后一个词进行过滤,仅仅因为在实际应用这些过滤器时,只剩下一个SubString值,最后一个.
如果您更改代码以便捕获循环范围内的SubString变量,它将起作用:
if (SubString != null && SubString.Length > 0)
{
String captured = SubString;
Int32 capturedId = SubStringAsInteger;
Result = Result.Where(c => (c.FirstName.Contains(captured)
|| c.LastName.Contains(captured)
|| c.Email.Contains(captured)
|| (c.ID == capturedId)
));
}
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