为什么我不能使用urlencode来编码json格式数据？

Question

我在python 2.7中有关于urlencode的问题:

>>> import urllib
>>> import json
>>> urllib.urlencode(json.dumps({'title':"hello world?",'anonymous':False,'needautocategory':True}))
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "/usr/local/lib/python2.7/urllib.py", line 1280, in urlencode
    raise TypeError
TypeError: not a valid non-string sequence or mapping object

Answer 1

urlencode可以编码一个字典,但不能编码.输出json.dumps是一个字符串.

根据您想要的输出,不要在JSON中编码dict:

>>> urllib.urlencode({'title':"hello world?",'anonymous':False,'needautocategory':True})
'needautocategory=True&anonymous=False&title=hello+world%EF%BC%81'

或将整个事物包裹在一个字典中:

>>> urllib.urlencode({'data': json.dumps({'title':"hello world?",'anonymous':False,'needautocategory':True})})
'data=%7B%22needautocategory%22%3A+true%2C+%22anonymous%22%3A+false%2C+%22title%22%3A+%22hello+world%5Cuff01%22%7D'

或使用quote_plus()代替(urlencode使用quote_plus的键和值):

>>> urllib.quote_plus(json.dumps({'title':"hello world?",'anonymous':False,'needautocategory':True}))
'%7B%22needautocategory%22%3A+true%2C+%22anonymous%22%3A+false%2C+%22title%22%3A+%22hello+world%5Cuff01%22%7D'

Answer 2

因为urllib.urlencode "将映射对象或两元素元组序列转换为"百分比编码"字符串...".你的字符串不是这些.

我想你需要urllib.quote或urllib.quote_plus.