ios如何让UITextView检测到一个水龙头？

Question

- (void)touchesBegan:(NSSet *)touches withEvent:(UIEvent *)event{
    NSLog(@"touchesBegan");

    //test
    UITouch *touch = [event allTouches] anyObject];
    if ([touch tapCount] == 2) {
        NSLog (@"tapcount 2");
        [self.textview becomeFirstResponder];

    }   

     else if ([touch tapCount] == 1) {
         NSLog (@"tapcount 1");
         [self.textview becomeFirstResponder];
         [self.view performSelector:@selector(select:)];


     }

}

- (void)touchesMoved:(NSSet *)touches withEvent:(UIEvent *)event{
    [super touchesBegan:touches withEvent:event];
    NSLog(@"touchesMoved");
}

- (void)touchesEnded:(NSSet *)touches withEvent:(UIEvent *)event{
    NSLog(@"****touchesEnded");
    [self.nextResponder touchesEnded: touches withEvent:event]; 
    NSLog(@"****touchesEnded");
    [super touchesEnded:touches withEvent:event];
    NSLog(@"****touchesEnded");
}

- (void)touchesCancelled:(NSSet *)touches withEvent:(UIEvent *)event{
    [super touchesCancelled:touches withEvent:event]; 
    NSLog(@"touchesCancelled");
}

我的问题:

我想在a上点击一次时模拟两次点击UITextView,这是此代码中的textview.但是当我在textview上点击一次或两次时,我不会从一次和两次点击中获得NSLog.我该怎么做才能让它发挥作用？

Answer 1

可能我会在这里使用两个手势识别器.

//...some stuff above here probably in you're controllers viewDidLoad

UITapGestureRecognizer *singleTap = [[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(singleTapRecognized:)];
singleTap.numberOfTapsRequired = 1;
[someTextView addGestureRecognizer:singleTap];
[singleTap release];

UITapGestureRecognizer *doubleTap = [[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(doubleTapRecognized:)];
doubleTap.numberOfTapsRequired = 2;
[someTextView addGestureRecognizer:doubleTap];
[doubleTap release];

选择器就像:

- (void)singleTapRecognized:(UIGestureRecognizer *)gestureRecognizer {
    NSLog(@"single tap");
    // ...etc
}

- (void)doubleTapRecognized:(UIGestureRecognizer *)gestureRecognizer {
    NSLog(@"double tap");
    // ...etc
}