我有一个包含如下列的数据库.
Id Date Value
1 12/01/2010 09:30 127.31
1 12/01/2010 09:31 133.41
1 12/01/2010 09:32 147.54
1 12/01/2010 09:34 155.66
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本质上,我存储与时间戳对应的值.但是,如果值为0,我不存储它(它是一个非常大的数据库,0经常发生,所以我们决定不包括这些行来节省空间).在上面的例子中,12/01/2010 09:33有一个0值,所以它没有存储.但是,当用户查询数据库时,他会执行类似的操作
select * from table where Id = '1' and Date > to_date('12/01/2010', 'MM/DD/YYYY')`
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我需要填补空白并提及0值的时间戳.我怎样才能做到这一点?
select
nvl(b.id,1) as id,
alldates.Date as Date,
nvl(b.value,0) as value
from
(select level/1440 + to_date('12/01/2010', 'MM/DD/YYYY') as Date
from dual
connect by level < 1440 --one day
) alldates
left join
(select * from table where Id = '1' and Date > to_date('12/01/2010', 'MM/DD/YYYY') b
on alldates.Date = b.Date
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更新(回复评论):
select
nvl(b.id,1) as id,
alldates.Date as Date,
nvl(b.value,0) as value,
nvl(b.value, lag(b.value) over (order by b.Date nulls last)) last_valid_value
from
(select level/1440 + to_date('12/01/2010', 'MM/DD/YYYY') as Date
from dual
connect by level < 1440 --one day
) alldates
left join
(select * from table where Id = '1' and Date > to_date('12/01/2010', 'MM/DD/YYYY') b
on alldates.Date = b.Date
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