mysql_fetch_array在zend框架中不起作用

Question

这是我到目前为止的代码: -

$db = $this->getInvokeArg('bootstrap')->getPluginResource('db')->getDbAdapter();
$sql = "select * from users";
$result = $db->fetchAll($sql);

echo "<table border='1'>
    <tr>
    <th>ID</th>
    <th>Firstname</th>
    <th>Lastname</th>
    <th>Email</th>
    <th>Username</th>
    <th>Password</th>
    </tr>
";

while($row = mysql_fetch_array($result)){
    echo "<tr>";
    echo "<td>" . $row['id'] . "</td>";
    echo "<td>" . $row['firstname'] . "</td>";
    echo "<td>" . $row['lastname'] . "</td>";
    echo "<td>" . $row['email'] . "</td>";
    echo "<td>" . $row['username'] . "</td>";
    echo "<td>" . $row['password'] . "</td>";
    echo "</tr>";
  }
echo "</table>";

我正在尝试这个,但我收到了这个错误: -

Warning: mysql_fetch_array() expects parameter 1 to be resource, array given in /var/www/datashow/application/controllers/IndexController.php on line 35 

Answer 1

Zend_Db不返回mysql结果对象.在使用Zend_Db抽象层时,您不会使用MySQL的函数; 你使用Zend的功能.在这种情况下,findAll已经将数据作为数组返回.