从jquery ajax中的json数组中访问各个值

Question

我在jQuery中有一个由AJAX返回的数组.我想迭代AJAX成功结果并从JSON数组中获取单个值.数据以字符串的形式返回.我正在使用jQuery $.ajax从服务器上获取它,这很好.

//my View
$.ajax({
    type: "POST",
    url:"http://localhost:8888/CodeIgniter/index.php/user/usercontroller/search",//controller function
    cache: false,
    data:{"responsible1":res1},
    success: function(data21) { 
        alert(data21);
    });
});

//data 21 alerts the following
{"taskname":"Coding","projname":"Easy Wedding"} 
{"taskname":"Maintain","projname":"Easy Wedding"}
{"taskname":"Flow Chart","projname":"Fnn"}
{"taskname":"development in ","projname":"Fnn"}
{"taskname":"flow chart","projname":"Art gallery"}

如何只访问个人taskname和/ projectname或如何转换data21为数组

Answer 1

只需添加dataType: "json"到您的请求中,您将获得数据作为对象,但如果您将返回数据放入这些括号中,这将会起作用:[]

否则使用这个

data21 = $.parseJSON('[' + data21.replace(/\"}/g, '"},').replace(/,$/, "") + ']');
console.log(data21);

例