通过引用c ++传递struct参数

Question

如何通过引用c ++传递struct参数,请参见下面的代码.

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <iostream>

using namespace std;
struct TEST
{
  char arr[20];
  int var;
};

void foo(char * arr){
 arr = "baby"; /* here need to set the test.char = "baby" */
}

int main () {
TEST test;
/* here need to pass specific struct parameters, not the entire struct */
foo(test.arr);
cout << test.arr <<endl;
}

所需的输出应该是宝贝.

Answer 1

我会在c ++中使用std :: string而不是c数组所以代码看起来像这样;

#include <stdio.h>
#include <stdlib.h>
#include <string>
#include <iostream>

using namespace std;
struct TEST
{
  std::string arr;
  int var;
};

void foo(std::string&  str){
  str = "baby"; /* here need to set the test.char = "baby" */
}

int main () {
  TEST test;
  /* here need to pass specific struct parameters, not the entire struct */
  foo(test.arr);
  cout << test.arr <<endl;
}