在C#中解压缩流

Question

我正在使用C#,我正在为互联网下载一个带有一个XML文件的zip文件.我希望加载这个XML文件.这是我到目前为止:

byte[] data;
WebClient webClient = new WebClient();
try {
    data = webClient.DownloadData(downloadUrl);
}
catch (Exception ex) {
    Console.WriteLine("Error in DownloadData (Ex:{0})", ex.Message);
    throw;
}

if (data == null) {
    Console.WriteLine("Bulk data is null");
    throw new Exception("Bulk data is null");
}

//Create the stream
MemoryStream stream = new MemoryStream(data);
XmlDocument document = new XmlDocument();

//Gzip
GZipStream gzipStream = new GZipStream(stream, CompressionMode.Decompress);

//Load report straight from the gzip stream
try {
    document.Load(gzipStream);
}
catch (Exception ex) {
    Console.WriteLine("Error in Load (Ex:{0})", ex.Message);
    throw;
}

在document.Load我总是得到以下异常:
GZip标头中的幻数不正确.确保传入GZip流.

我做错了什么？

Answer 1

我使用的是SharpZipLib,效果很好!

下面是一个封装库的函数

 public static void Compress(FileInfo sourceFile, string destinationFileName,string destinationTempFileName)
        {
            Crc32 crc = new Crc32();
            string zipFile = Path.Combine(sourceFile.Directory.FullName, destinationTempFileName);
            zipFile = Path.ChangeExtension(zipFile, ZIP_EXTENSION);

            using (FileStream fs = File.Create(zipFile))
            {
                using (ZipOutputStream zOut = new ZipOutputStream(fs))
                {
                    zOut.SetLevel(9);
                    ZipEntry entry = new ZipEntry(ZipEntry.CleanName(destinationFileName));

                    entry.DateTime = DateTime.Now;
                    entry.ZipFileIndex = 1;
                    entry.Size = sourceFile.Length;

                    using (FileStream sourceStream = sourceFile.OpenRead())
                    {
                        crc.Reset();
                        long len = sourceFile.Length;
                        byte[] buffer = new byte[bufferSize];
                        while (len > 0)
                        {
                            int readSoFar = sourceStream.Read(buffer, 0, buffer.Length);
                            crc.Update(buffer, 0, readSoFar);
                            len -= readSoFar;
                        }
                        entry.Crc = crc.Value;
                        zOut.PutNextEntry(entry);

                        len = sourceStream.Length;
                        sourceStream.Seek(0, SeekOrigin.Begin);
                        while (len > 0)
                        {
                            int readSoFar = sourceStream.Read(buffer, 0, buffer.Length);
                            zOut.Write(buffer, 0, readSoFar);
                            len -= readSoFar;
                        }
                    }
                    zOut.Finish();
                    zOut.Close();
                }
                fs.Close();
            }
        }

Answer 2

显然SharpZipLib现在没有维护,你可能想避免它:https: //stackoverflow.com/a/593030

在.NET 4.5中,现在内置了对zip文件的支持,因此对于您的示例,它将是:

var data = new WebClient().DownloadData(downloadUrl);

//Create the stream
var stream = new MemoryStream(data);

var document = new XmlDocument();

//zip
var zipArchive = new ZipArchive(stream);

//Load report straight from the zip stream
document.Load(zipArchive.Entries[0].Open());

Answer 3

如果您的字节数组包含一个带有单个文件的zip存档，则可以使用ZipArchive该类来获取包含文件数据的未压缩字节数组。 ZipArchive包含在.NET 4.5的程序集中System.IO.Compression.FileSystem（您需要显式引用它）。

根据此答案改编的以下功能对我有用：

public static byte[] UnzipSingleEntry(byte[] zipped)
{
    using (var memoryStream = new MemoryStream(zipped))
    {
        using (var archive = new ZipArchive(memoryStream))
        {
            foreach (ZipArchiveEntry entry in archive.Entries)
            {
                using (var entryStream = entry.Open())
                {
                    using (var reader = new BinaryReader(entryStream))
                    {
                        return reader.ReadBytes((int)entry.Length);
                    }
                }
            }
        }
    }
    return null; // To quiet my compiler
}