Jar*_*red 3 python qt signals pyqt slot
有没有办法判断信号是否已连接到某个功能?
即我想看看signals.siSelectionChange是否连接到任何东西
signals.siSelectionChange.connect( self.SelAsSiAssets )
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ale*_*sdm 10
您可以使用QObject.receivers获取连接功能的计数.我用它如下,在closeEvent()QWidget中,我用作窗口:
receiversCount = self.receivers(QtCore.SIGNAL("siSelectionChanged()"))
if receiversCount > 0:
self.sigChanged.disconnect()
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请注意,参数字符串中的签名必须与真实签名匹配.
小智 7
因为我用 PyQt5 尝试过,但似乎不存在QtCore.SIGNAL. 我用isSignalConnectedQObject的方法尝试了一下。QMetaMethod.fromSignal使用此选项时您将面临的另一个问题是PyQt5 库中没有。
结果我写了一个getSignal函数。
from PyQt5.QtCore import QMetaMethod
from PyQt5.QtCore import QObject
def getSignal (oObject : QObject, strSignalName : str):
oMetaObj = oObject.metaObject()
for i in range (oMetaObj.methodCount()):
oMetaMethod = oMetaObj.method(i)
if not oMetaMethod.isValid():
continue
if oMetaMethod.methodType () == QMetaMethod.Signal and \
oMetaMethod.name() == strSignalName:
return oMetaMethod
return None
from PyQt5.QtCore import pyqtSignal
if __name__ == "__main__":
class A (QObject):
sigB = pyqtSignal()
def __init__ (self):
super().__init__()
oA = A ()
print ("is 'sigB' connected:", oA.isSignalConnected (getSignal(oA, "sigB")))
oA.sigB.connect (lambda : print("sigB emitted!"))
oA.sigB.emit()
print ("is 'sigB' connected:", oA.isSignalConnected (getSignal(oA, "sigB")))
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输出:
is 'sigB' connected: False
sigB emitted!
is 'sigB' connected: True
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