jbc*_*dge 43 javascript url parsing
我正在尝试将数据从一个页面传递到另一个页面.
www.mints.com?name=something
如何name
使用JavaScript 阅读?
Tom*_*lak 62
function parseURLParams(url) {
var queryStart = url.indexOf("?") + 1,
queryEnd = url.indexOf("#") + 1 || url.length + 1,
query = url.slice(queryStart, queryEnd - 1),
pairs = query.replace(/\+/g, " ").split("&"),
parms = {}, i, n, v, nv;
if (query === url || query === "") return;
for (i = 0; i < pairs.length; i++) {
nv = pairs[i].split("=", 2);
n = decodeURIComponent(nv[0]);
v = decodeURIComponent(nv[1]);
if (!parms.hasOwnProperty(n)) parms[n] = [];
parms[n].push(nv.length === 2 ? v : null);
}
return parms;
}
Run Code Online (Sandbox Code Playgroud)
使用方法如下:
var urlString = "http://www.foo.com/bar?a=a+a&b%20b=b&c=1&c=2&d#hash";
urlParams = parseURLParams(urlString);
Run Code Online (Sandbox Code Playgroud)
它返回一个像这样的对象:
{
"a" : ["a a"], /* param values are always returned as arrays */
"b b": ["b"], /* param names can have special chars as well */
"c" : ["1", "2"] /* an URL param can occur multiple times! */
"d" : [null] /* parameters without values are set to null */
}
Run Code Online (Sandbox Code Playgroud)
所以
parseURLParams("www.mints.com?name=something")
Run Code Online (Sandbox Code Playgroud)
给
{name: ["something"]}
Run Code Online (Sandbox Code Playgroud)
编辑:此答案的原始版本使用基于正则表达式的URL解析方法.它使用了较短的功能,但方法存在缺陷,我用适当的解析器替换它.
Fra*_* Yu 11
现在是2019年,不需要任何手写的解决方案或第三方库。如果要在浏览器中解析当前页面的URL:
# running on https://www.example.com?name=n1&name=n2
let params = new URLSearchParams(location.search);
params.get('name') # => "n1"
params.getAll('name') # => ["n1", "n2"]
Run Code Online (Sandbox Code Playgroud)
如果要解析随机URL,请在浏览器或Node.js中:
let url = 'https://www.example.com?name=n1&name=n2';
let params = (new URL(url)).searchParams;
params.get('name') # => "n1"
params.getAll('name') # => ["n1", "n2"]
Run Code Online (Sandbox Code Playgroud)
它利用了现代浏览器附带的URLSearchParams接口。
小智 10
你可以轻松做到这一点
const shopId = new URLSearchParams(window.location.search).get('shop_id');
console.log(shopId);
Run Code Online (Sandbox Code Playgroud)
我认为这也应该有效:
function $_GET(q,s) {
s = (s) ? s : window.location.search;
var re = new RegExp('&'+q+'=([^&]*)','i');
return (s=s.replace(/^\?/,'&').match(re)) ?s=s[1] :s='';
}
Run Code Online (Sandbox Code Playgroud)
只需将其称为:
var value = $_GET('myvariable');
Run Code Online (Sandbox Code Playgroud)
试试这个方法
var url_string = window.location;
var url = new URL(url_string);
var name = url.searchParams.get("name");
var tvid = url.searchParams.get("id");
Run Code Online (Sandbox Code Playgroud)