ama*_*ent 8 java swing jinternalframe jdesktoppane
当我在JDesktopPane中有一个JInternalFrame时,JInternalFrame是可移动的(这很好).但是,可以将它移到JDesktopPane的可见范围之外(我不是很喜欢)
为了亲眼看看,这里有一些示例代码:
public static void main(String[] args) {
JFrame frame = new JFrame("JDesktopPane");
JDesktopPane tableDisplay = new JDesktopPane();
JInternalFrame internalFrame = new JInternalFrame("JInternalFrame",true,true,true,true);
internalFrame.setContentPane(new JLabel("Content"));
internalFrame.pack();
internalFrame.setVisible(true);
tableDisplay.add(internalFrame, JDesktopPane.POPUP_LAYER);
frame.setContentPane(tableDisplay);
frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
frame.setMinimumSize(new Dimension(400, 300));
frame.setVisible(true);
}
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是否可以设置JInternalFrame或JDesktopPane,以便它们不允许这样做?
负责移动/调整大小的协作者是DesktopPaneManager.所以我会尝试将移动限制在窗格内.这是一个快速而肮脏的概念证明:
JDesktopPane background = new JDesktopPane();
JInternalFrame internalFrame = new JInternalFrame("Internal Frame",
true, true, true, true);
DesktopManager manager = new DefaultDesktopManager() {
/** This moves the <code>JComponent</code> and repaints the damaged areas. */
@Override
public void setBoundsForFrame(JComponent f, int newX, int newY, int newWidth, int newHeight) {
boolean didResize = (f.getWidth() != newWidth || f.getHeight() != newHeight);
if (!inBounds((JInternalFrame) f, newX, newY, newWidth, newHeight)) return;
f.setBounds(newX, newY, newWidth, newHeight);
if(didResize) {
f.validate();
}
}
protected boolean inBounds(JInternalFrame f, int newX, int newY, int newWidth, int newHeight) {
if (newX < 0 || newY < 0) return false;
if (newX + newWidth > f.getDesktopPane().getWidth()) return false;
if (newY + newHeight > f.getDesktopPane().getHeight()) return false;
return true;
}
};
background.setDesktopManager(manager);
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有一些问题需要解决,显然:-) Fi
编辑
只是为了澄清:"没有反应"我的意思是用户必须释放并再次按下/拖动(一旦内部框架已经达到桌面边界)进一步移动.这并不奇怪,因为BorderListener(它是由BasicInternalFrame安装的mouseListener)保持一些与初始按下相关的状态,然后请求相对于该初始位置重新定位.拖动鼠标框架卡在某处会混淆内部状态.
有趣的是,看看代码,看起来有意图限制运动不要把它推到外面,
// Make sure we stay in-bounds
if(newX + i.left <= -__x)
newX = -__x - i.left + 1;
if(newY + i.top <= -__y)
newY = -__y - i.top + 1;
if(newX + __x + i.right >= pWidth)
newX = pWidth - __x - i.right - 1;
if(newY + __y + i.bottom >= pHeight)
newY = pHeight - __y - i.bottom - 1;
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但这与当前鼠标位置有关.
完全归功于kleopatra让我指向正确的方向.
我想我已经解决了无反应问题,并且在这里分享我的解决方案.按照kleopatra的回答,如果鼠标点位于窗格之外,则内部框架位于窗格的边缘.此外,这继续跟随鼠标 - 即如果您将鼠标移离窗格底部,然后向窗口的右侧移动,则框架将沿着窗格的底部,然后向右移动窗格的沙子.
public class BoundedDesktopManager extends DefaultDesktopManager {
@Override
public void beginDraggingFrame(JComponent f) {
// Don't do anything. Needed to prevent the DefaultDesktopManager setting the dragMode
}
@Override
public void beginResizingFrame(JComponent f, int direction) {
// Don't do anything. Needed to prevent the DefaultDesktopManager setting the dragMode
}
@Override
public void setBoundsForFrame(JComponent f, int newX, int newY, int newWidth, int newHeight) {
boolean didResize = (f.getWidth() != newWidth || f.getHeight() != newHeight);
if (!inBounds((JInternalFrame) f, newX, newY, newWidth, newHeight)) {
Container parent = f.getParent();
Dimension parentSize = parent.getSize();
int boundedX = (int) Math.min(Math.max(0, newX), parentSize.getWidth() - newWidth);
int boundedY = (int) Math.min(Math.max(0, newY), parentSize.getHeight() - newHeight);
f.setBounds(boundedX, boundedY, newWidth, newHeight);
} else {
f.setBounds(newX, newY, newWidth, newHeight);
}
if(didResize) {
f.validate();
}
}
protected boolean inBounds(JInternalFrame f, int newX, int newY, int newWidth, int newHeight) {
if (newX < 0 || newY < 0) return false;
if (newX + newWidth > f.getDesktopPane().getWidth()) return false;
if (newY + newHeight > f.getDesktopPane().getHeight()) return false;
return true;
}
}
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