带有createSQLQuery的ResultTransformer强制实体字段中没有camelCase

fre*_*dev 17 postgresql hibernate

我有一个SQL查询如下:

List<Employee> employees = getCurrentSession()
                    .createSQLQuery(
                            "select"
                                    + e.id as id,e.first_name as firstName,e.password as password
                                    + "from employee e,employee_role er,role r where e.employee_id=er.employee_id and er.role_id=r.role_id and r.name='ROLE_ADMIN' ")
                    .setResultTransformer(Transformers.aliasToBean(Employee.class))
                    .list();
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我在Employee中有一个名为firstName的属性,但是当在单元测试中尝试在dao上运行时,我收到以下异常:

org.hibernate.PropertyNotFoundException: Could not find setter for firstname on class com.app.domain.Employee
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我不知道hibernate从这个firstname属性中得到了什么?我的查询中没有对它?

任何方式的解决方法是将属性更改为firstname,getter,setter,但任何想法为什么hibernate正在进行此类行为,以及如何避免它,因为我想在我的域中使用camelCase,请指教.

Ken*_*han 23

您可以使用addScalar(String columnAlias,Type type)显式声明本机SQL的列别名:

  getCurrentSession()
  .createSQLQuery( "select e.id as id,e.first_name as firstName,e.password as password from xxxxxx")
                .addScalar("id",StandardBasicTypes.INTEGER )
                .addScalar("firstName",StandardBasicTypes.STRING )
                .addScalar("password",StandardBasicTypes.STRING )
                .setResultTransformer(Transformers.aliasToBean(Employee.class))
                .list();
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Mat*_*ood 17

对于更简单的解决方案,请将查询中的标识符双重引用发送到服务器.代替

e.first_name as firstName
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它应该读

e.first_name as "firstName"
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在PostgreSQL中,双引号标识符会强制区分大小写.不带引号,它(大部分)遵循SQL标准并折叠为单个案例(尽管标准是大写的小写).