为什么jshint不能将赋值识别为表达式？

Question

我如何修改这些行以使jshint满意？

赋值是一种表达.为什么jshint不理解这个？显然翻译是这样的.

Line 572: while(bookmark_element=bookmark_list[iterator++])

Expected a conditional expression and instead saw an assignment.


Line 582: while(bookmark_element=bookmark_list[iterator++])

Expected a conditional expression and instead saw an assignment.


Line 623: while(element_iterator=element_iterator.nextSibling)

Expected a conditional expression and instead saw an assignment.

Answer 1

如果你真的想听JSHint,请将表达式转换为布尔值:

while (!!(bookmark_element=bookmark_list[iterator++]))

! means: Something that evaluates to true is converted to false,
         something that evaluates to false is converted to true.

所以,!!意思是:将某些东西转换为条件表示.

Answer 2

/*jshint boss:true */

试验选项.

Answer 3

我确信jshint理解表达式很好,只是大多数人写的if (a = b)实际意味着if (a == b)所以这会产生警告.

由于您的代码是您想要的,您可以添加一个明确的测试:

while ((element_iterator = element_iterator.nextSibling) !== null) { ... }