import csv
a=[]
with open('large.csv','w') as f1:
writer=csv.writer(f1, delimiter='\t',lineterminator='\n',)
for i in range(1000000):
for j in range(i+1):
a.append(i+j*0.2)
#print i,j,a
#want to write into same csv file???
'''like
0 1 2......999999
0 0.0
1 1.0 1.2
2 2.0 2.2 2.4
. .....
. .....
999999
'''
a=[]
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我这样做,以避免两次相同的计算研究和列表"A"将变得很大,我必须重新初始化.所以(外循环的一个迭代后),我想要的清单(前再次获得初始化)写入CSV以上述方式提交,但我无法这样做......请帮忙.
eum*_*iro 14
你想做这样的事吗?
import csv
with open('large.csv','w') as f1:
writer=csv.writer(f1, delimiter='\t',lineterminator='\n',)
for i in range(1000000):
row = [i + j*0.2 for j in range(i+1)]
writer.writerow(row)
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或者还有行/列标题:
import csv
with open('large.csv','w') as f1:
writer=csv.writer(f1, delimiter='\t',lineterminator='\n',)
writer.writerow([''] + range(1000000))
for i in range(1000000):
row = [i] + [i + j*0.2 for j in range(i+1)]
writer.writerow(row)
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后者返回以下文件(我用10替换了1000000):
0 1 2 3 4 5 6 7 8 9
0 0.0
1 1.0 1.2
2 2.0 2.2 2.4
3 3.0 3.2 3.4 3.6
4 4.0 4.2 4.4 4.6 4.8
5 5.0 5.2 5.4 5.6 5.8 6.0
6 6.0 6.2 6.4 6.6 6.8 7.0 7.2
7 7.0 7.2 7.4 7.6 7.8 8.0 8.2 8.4
8 8.0 8.2 8.4 8.6 8.8 9.0 9.2 9.4 9.6
9 9.0 9.2 9.4 9.6 9.8 10.0 10.2 10.4 10.6 10.8
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