当我尝试输出字符串时,它不会在空格后输出文本.它应该询问学生姓名,然后在被问到时输出.这是C++.我没有更多信息要提供,但该网站不会让我发布它所以这句话在这里.
/***************************************************/
/* Author: Sam LaManna */
/* Course: CSC 135 Lisa Frye */
/* Assignment: Program 4 Grade Average */
/* Due Date: 10/10/11 */
/* Filename: program4.cpp */
/* Purpose: Write a program that will process */
/* students are their grades. It will */
/* also read in 10 test scores and */
/* compute their average */
/***************************************************/
#include <iostream> //Basic input/output
#include <iomanip> //Manipulators
using namespace std;
string studname (); //Function declaration for getting students name
int main()
{
string studentname = "a"; //Define Var for storing students name
studentname = studname (); //Store value from function for students name
cout << "\n" << "Student name is: " <<studentname << "\n" << "\n"; //String output test
return 0;
}
/***************************************************/
/* Name: studname */
/* Description: Get student's first and last name */
/* Paramerters: N/A */
/* Return Value: studname */
/***************************************************/
string studname()
{
string studname = "default";
cout << "Please enther the students name: ";
cin >> studname;
return studname;
}
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小智 5
您应该使用getline()函数而不是简单函数,仅cin用于cin在空格之前获取字符串.
istream& getline ( istream& is, string& str, char delim );
istream& getline ( istream& is, string& str );
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从中提取字符is并将其存储到str找到分隔符字符.
分隔符delim用于第一个函数版本,'\n'(换行符)用于第二个函数版本.如果到达文件末尾或者在输入操作期间发生某些其他错误,则提取也会停止.
如果找到分隔符,则将其提取并丢弃,即不存储分隔符,并且在其之后开始下一个输入操作.
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