Pan*_*kaj 22 c# xml-serialization
我正在使用c#序列化一个对象.我得到的结果如下所示
<?xml version="1.0"?>
<Users xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<Users>
<User Id="11005477969327" CreateDate="06/03/2011" LastSendDate="1/1/0001" />
<User Id="11034688201594" CreateDate="04/22/2012" LastSendDate="1/1/0001" />
<Users
</User>
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但我希望得到这种格式的结果.
<?xml version="1.0"?>
<Users>
<User Id="11005477969327" SendDate="1/1/0001" NextSendDate="2/7/2012 11:13:30 AM" />
<User Id="11034688201594" SendDate="1/1/0001" NextSendDate="2/7/2012 11:13:30 AM" />
</Users>
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我的代码
public class Users
{
[XmlArray("Users")]
public List<User> ListData { get; set; }
public string GetXML()
{
System.IO.MemoryStream ms = new System.IO.MemoryStream();
XmlSerializer sr = new XmlSerializer(typeof(Users));
sr.Serialize(ms, this);
ms.Position = 0;
return System.Text.Encoding.UTF8.GetString(ms.ToArray());
}
}
public class User
{
[XmlAttribute("Id")]
public Int64 UserId { get; set; }
[XmlAttribute("CreateDate")]
public string CreateDate { get; set; }
[XmlAttribute("LastSendDate")]
public string LastSendDate { get; set; }
}
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Vla*_*lov 60
你应该只需更换[XmlArray("Users")]与[XmlElement("User")]
此属性告诉序列化程序,您要将所有这些用户项目存储在特定节点"用户"下,如果您将其替换为XmlElement,则serialzer将根据您的需要将所有这些用户内联(位于第一个用户标记下)存储.
至于xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"名称空间.它们是自动添加的,但它们是无害的,因为所有元素都在默认命名空间中.您可以在XmlSerializer通话中添加以下代码,以便删除这些代码:
var xns = new XmlSerializerNamespaces();
var serializer = new XmlSerializer(users.GetType());
xns.Add(string.Empty, string.Empty);
//...
serializer.Serialize(stream, users, xns);
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小智 5
你应该写:
XmlSerializer sr = new XmlSerializer(typeof(Users));
XmlSerializerNamespaces ns = new XmlSerializerNamespaces();
ns.Add("","");
sr.Serialize(ms, this, ns);
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