SQL - 计算有序列表中的更改数

Question

说我有一个有两列的表(日期和价格).如果我选择一系列日期,那么有没有办法计算价格变化的数量？

例如:

   Date   | Price
22-Oct-11 |  3.20
23-Oct-11 |  3.40
24-Oct-11 |  3.40
25-Oct-11 |  3.50
26-Oct-11 |  3.40
27-Oct-11 |  3.20
28-Oct-11 |  3.20

在这种情况下,我希望它返回4个价格变化的计数.

提前致谢.

Answer 1

您可以使用分析函数LEAD并LAG访问结果集的上一行和下一行,然后使用它来查看是否存在更改.

SQL> ed
Wrote file afiedt.buf

  1  with t as (
  2    select date '2011-10-22' dt, 3.2 price from dual union all
  3    select date '2011-10-23', 3.4 from dual union all
  4    select date '2011-10-24', 3.4 from dual union all
  5    select date '2011-10-25', 3.5 from dual union all
  6    select date '2011-10-26', 3.4 from dual union all
  7    select date '2011-10-27', 3.2 from dual union all
  8    select date '2011-10-28', 3.2 from dual
  9  )
 10  select sum(is_change)
 11    from (
 12      select dt,
 13             price,
 14             lag(price) over (order by dt) prior_price,
 15             (case when lag(price) over (order by dt) != price
 16                   then 1
 17                   else 0
 18               end) is_change
 19*       from t)
SQL> /

SUM(IS_CHANGE)
--------------
             4