你能帮我从下面的地图中找出简单删除中的错误(通知输出在它下面)吗?
public class Issue {
...
def allButThis() {
println "allButThis ..."
def all = Issue.list()
println "all is ${all}"
all.remove(this.id)
println "all with ${this.id} removed: ${all}"
return all
}
String toString() {return "${id}: ${title}"}
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当我运行它时,我得到以下结果,即项目2未按预期被删除
allButThis ...
all is [1: Issue-1, 2: Issue-2, 3: Issue-3]
all with 2 removed: [1: Issue-1, 2: Issue-2, 3: Issue-3]
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据我所知,这个删除应该有效,例如 http://groovy.codehaus.org/JN1035-Maps,其中"删除"在页面下方描述三分之一.
我正在使用Grails 1.3.7.
谢谢
PS我添加了我的toString()方法(上面),也许我自欺欺人了.
-------------更新----------
我删除了我的toString()方法,并遵循Rob的解决方案,即:
all.remove(this)
println "all with ${this} removed: ${all}"
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产生:
all is [momentum.Issue : 1, momentum.Issue : 2, momentum.Issue : 3]
all with momentum.Issue : 2 removed: [momentum.Issue : 1, momentum.Issue : 3]
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def all = Issue.list()
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这是一个列表,而不是地图.
所以要从这个列表中删除:
all.remove(this)
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代替.
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