用于按钮的UITapGestureRecognizer问题

Question

我做了以下事情:

 buttonPlaylistView = [[UIButton alloc] initWithFrame:CGRectMake(self.view.frame.size.width *(urlList.count+1), 0, self.view.frame.size.width, self.view.frame.size.height)];
            buttonPlaylistView.tag = 0;

 UITapGestureRecognizer *doubleTap3 = [[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(handleDoubleTap:)];
            [doubleTap3 setNumberOfTapsRequired:2];
            [buttonPlaylistView addGestureRecognizer:doubleTap3];
            [doubleTap3 release];

-(void) handleDoubleTap:(UITapGestureRecognizer *)sender{
    if(sender.state == UIGestureRecognizerStateEnded)

    int x = [sender tag];
    return;
}

但我明白SIGAGRT这一点:int x = [sender tag];说:

[UITapGestureRecognizer tag]: unrecognized selector sent to instance 0x61280b0
*** Terminating app due to uncaught exception 'NSInvalidArgumentException', reason: '-[UITapGestureRecognizer tag]: unrecognized selector sent to instance 0x61280b0'

现在:问题是什么,解决方案是什么？谢谢

Answer 1

-(void) handleDoubleTap:(UITapGestureRecognizer *)sender
{
    if(sender.state == UIGestureRecognizerStateEnded)
    {
      int x = [sender.view tag];
    }
}

将解决问题.