Ada*_*sek 15 union ruby-on-rails active-relation ruby-on-rails-3
我需要能够UNION使用ActiveRelation 链接任意数量的子选择.
我对ARel的实现有点困惑,因为它似乎假设UNION是二进制操作.
然而:
( select_statement_a ) UNION ( select_statement_b ) UNION ( select_statement_c )
Run Code Online (Sandbox Code Playgroud)
是有效的SQL.如果不做令人讨厌的字符串替换,这可能吗?
bra*_*ing 11
你可以做得比Adam Lassek提出的要好一些,尽管他在正确的轨道上.我刚刚解决了类似的问题,试图从社交网络模型中获取朋友列表.朋友可以通过各种方式自动获取,但我希望有一个可以处理进一步链接的ActiveRelation友好查询方法.所以我有
class User
has_many :events_as_owner, :class_name => "Event", :inverse_of => :owner, :foreign_key => :owner_id, :dependent => :destroy
has_many :events_as_guest, :through => :invitations, :source => :event
def friends
friends_as_guests = User.joins{events_as_guest}.where{events_as_guest.owner_id==my{id}}
friends_as_hosts = User.joins{events_as_owner}.joins{invitations}.where{invitations.user_id==my{id}}
User.where do
(id.in friends_as_guests.select{id}
) |
(id.in friends_as_hosts.select{id}
)
end
end
end
Run Code Online (Sandbox Code Playgroud)
它利用了Squeels子查询支持.生成的SQL是
SELECT "users".*
FROM "users"
WHERE (( "users"."id" IN (SELECT "users"."id"
FROM "users"
INNER JOIN "invitations"
ON "invitations"."user_id" = "users"."id"
INNER JOIN "events"
ON "events"."id" = "invitations"."event_id"
WHERE "events"."owner_id" = 87)
OR "users"."id" IN (SELECT "users"."id"
FROM "users"
INNER JOIN "events"
ON "events"."owner_id" = "users"."id"
INNER JOIN "invitations"
ON "invitations"."user_id" =
"users"."id"
WHERE "invitations"."user_id" = 87) ))
Run Code Online (Sandbox Code Playgroud)
通过对上述代码稍作修改,演示了需要可变数量组件的替代模式
def friends
friends_as_guests = User.joins{events_as_guest}.where{events_as_guest.owner_id==my{id}}
friends_as_hosts = User.joins{events_as_owner}.joins{invitations}.where{invitations.user_id==my{id}}
components = [friends_as_guests, friends_as_hosts]
User.where do
components = components.map { |c| id.in c.select{id} }
components.inject do |s, i|
s | i
end
end
end
Run Code Online (Sandbox Code Playgroud)
对于OP的确切问题,这里有一个粗略的猜测
class Shift < ActiveRecord::Base
def self.limit_per_day(options = {})
options[:start] ||= Date.today
options[:stop] ||= Date.today.next_month
options[:per_day] ||= 5
queries = (options[:start]..options[:stop]).map do |day|
where{|s| s.scheduled_start >= day}.
where{|s| s.scheduled_start < day.tomorrow}.
limit(options[:per_day])
end
where do
queries.map { |c| id.in c.select{id} }.inject do |s, i|
s | i
end
end
end
end
Run Code Online (Sandbox Code Playgroud)