Python:从`datetime.datetime`转换为`time.time`

Question

在Python中,如何将a datetime.datetime转换为float我从time.time函数中获得的那种？

Answer 1

使用time tuple方法并不难,并且仍然保留微秒:

>>> t = datetime.datetime.now()
>>> t
datetime.datetime(2011, 11, 5, 11, 26, 15, 37496)

>>> time.mktime(t.timetuple()) + t.microsecond / 1E6
1320517575.037496

Answer 2

time.mktime(dt_obj.timetuple())

应该做的伎俩.

Answer 3

给定一个datetime.datetime对象dt,你可以使用

(dt - datetime.datetime.utcfromtimestamp(0)).total_seconds()

例:

>>> dt = datetime.datetime.now(); t = time.time()
>>> t
1320516581.727343
>>> (dt - datetime.datetime.utcfromtimestamp(0)).total_seconds()
1320516581.727296

请注意,该timedelta.total_seconds()方法是在Python 2.7中引入的.

Answer 4

我知道这是一个老问题，但是在python 3.3+中，现在有了使用datetime.timestamp（）方法执行此操作的更简单方法：

from datetime import datetime
timestamp = datetime.now().timestamp()

Answer 5

的组合datetime.timetuple()和time.mktime():

>>> import datetime
>>> import time
>>> now = datetime.datetime.now()
>>> secondsSinceEpoch = time.mktime(now.timetuple())