F21*_*F21 9 php oop design-patterns
无论如何(或模式)是否强制调用父方法?
我有一个像这样的抽象类:
abstract class APrimitive{
public function validate(){
//Do some stuff that applies all classes that extend APrimitive
}
}
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然后我有一些扩展到APrimitive"base"的类:
class CSophisticated extends APrimitive{
public function validate(){
//First call the parent version:
parent::validate();
//Then do something more sophisticated here.
}
}
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问题是,如果我们在几个月后回到代码中,并使用方法创建一些类似CSophisticated的类validate(),那么我们可能会忘记parent::validate()在该方法中调用它.
请注意,某些CS复杂类可能没有该validate()方法,因此将调用父版本.
我知道可以在某个地方发表评论,提醒程序员打电话parent::validate(),但是有更好的方法吗?如果parent::validate()在validate()方法中没有进行调用,则可能是一种自动抛出异常的方法.
Luc*_*ore 10
您可以使用以下方法强制执行呼叫:
abstract class APrimitive{
final public function validate(){
//do the logic in validate
overrideValidate();
}
protected function overrideValidate(){
}
}
class CSophisticated extends APrimitive{
protected function overrideValidate(){
}
}
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现在只validate允许调用,这将调用您的重写方法.语法可能稍微偏离(PHP不是我选择的语言),但该原则适用于大多数OOP语言.
进一步解释:
abstract class APrimitive{
public function validate(){
echo 'APrimitive validate call.';
overrideValidate();
}
protected function overrideValidate(){
}
}
class CSophisticated extends APrimitive{
protected function overrideValidate(){
echo 'CSophisticated call.';
}
}
CSophisticated foo;
foo.overrideValidate(); //error - overrideValidate is protected
foo.validate(); //
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输出:
APrimitive validate call.
CSophisticated call.
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函数调用基本上执行以下操作:
foo.validate() -> APrimitive.validate() -> ASophisticated.overrideValidate() (or APrimitive.overrideValidate() if it wasn't overriden)
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您正在寻找模板方法模式.
此模式允许您通过子类化以某种方式修改操作,但确保始终涉及基类.
class Base {
//declared final so it can't be overridden
public final function validate() {
//perform base class operations here
//then forward to the sub class
$this->doValidate();
//do some more base class stuff here if needed
}
//override this method to alter validate operation
protected function doValidate(){
//no-op in base
}
}
class Sub {
protected function doValidate() {
//if required
//make the sub-class contribution to validate here
}
}
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