给出以下示例:
container = [ (1, "a") ,
(40, "b") ,
(24, "c") , #we intend to change this
(103, "d")
]
for k,v in container:
if k == 24:
v += " good"
print container
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容器中的(24,"c")数据对仍将保持其原始值,并且不会更改为(24,"c good").在迭代期间将其改为(24,"c good")的方法是什么?
我使用python 2.7,但也欢迎使用3.x示例.
谢谢.
您可以使用enumerate()您正在查看的容器项的索引的跟踪:
for i, (k,v) in enumerate(container):
if k == 24:
container[i] = (k, v+" good")
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