没有基础表的Hibernate实体

idb*_*ley 10 java hibernate jpa-2.0

我有一个非常难看的遗留数据库系统,我需要与之集成.基本上我在系统上做一些只读报告,我不想设置代表我正在处理的每个表的一千个实体.相反,我想为我生成的每个报告类型定义一个实体(实质上是来自不同表的一堆列的联合),然后让hibernate映射来讨厌(许多已加入,很多联合) sql查询到这样的实体列表.

问题是:我可以创建一个没有基础表的实体,并使用sql语句填充所述实体的列表吗?

谢谢!

Jas*_*rel 8

我们一直这样做 - 这就是我们如何做到的:

  1. 定义一个简单的类bean对象来表示报表中的每一行输出:

    public class CityStateRevenueReport {
    
        private String mId;
        private String mState;
        private String mCity;
        private Double mRevenue;
    
        public String getId() { return mId; }
        public void setId(String i) { mId = i; }
        public String getState() { return mState; }
        public void setState(String s) { mState = s; }
        public String getCity() { return mCity; }
        public void setCity(String c) { mCity = c; }
        public Double getReveneue() { return mRevenue; }
        public void setRevneue(Double d) { mRevenue = d; }
    }
    
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  2. 定义一个hibernate映射文件,CityStateRevneueReport.hbm.xml:

    <?xml version="1.0" ?>
    <!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN" "http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd&quot;>
    <hibernate-mapping>
        <class entity-name="CityStateRevenueReport">
            <id name="Id" type="java.lang.String" column="report_id">
                <generator class="sequence" />
            </id>
            <property name="city" type="string" column="city" />
            <property name="state" type="string" column="state" />
            <property name="revenue" type="double" column="revenue" />
        </class>
        <sql-query name="runReport">
            <![CDATA[ 
            SELECT {r.*} FROM 
                (select some_id_value as report_id, 
                        state_abbreviation as state, 
                        city_name as city, 
                        dollar_amount as revenue 
                   from -- tables, joins, other SQL insanity 
                 ) r
            ]]>
            <return alias="r" class="CityStateRevenueReport" />
        </sql-query>
    </hibernate-mapping>
    
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  3. 然后运行查询并填充实例:

    public List<CityStateRevenueReport> runReport() {
    
        List<CityStateRevenueReport> reports = 
                                 new ArrayList<CityStateRevenueReport>();
        List<HashMap> maps = session.getNamedQuery("runReport").list()
        for ( HashMap map : results ) {
            CityStateRevenueReport report = new CityStateRevenueReport();
            report.setState(map.get("state"));
            report.setCity(map.get("city"));
            report.setRevenue(Double.parseDouble(map.get("revenue"));
            reports.add(report);
        }
        return reports;
    }
    
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