Lis*_*ssy 9 javascript mobile-safari ipad
我们有一个iPad应用程序正在我们的旧iPad上工作.
我们使用var x = window.open(url)打开外部链接
在一天结束时,当用户关闭应用程序的这一部分时,我们会浏览它打开的所有窗口并为每个窗口执行x.close(),一切都很好.
使用IOS 5测试新iPad和可爱的选项卡,打开新窗口(虽然现在它们以标签打开)很好,但是x.close()似乎不一定关闭x,它可能关闭窗口y或ž.执行x.focus()或y.focus()工作正常,正确的选项卡成为焦点,但关闭似乎只是选择它想要的任何选项卡.
这是一个错误还是我做错了什么？示例程序:
<html>
<head></head>
<body>
<script>
//The openWindow array will hold the handles of all open child windows
var openWindow = new Array();
var win1;
var win2;
//Track open adds the new child window handle to the array.
function trackOpen(winName) {
openWindow[openWindow.length]=winName;
}
//loop over all known child windows and try to close them. No error is
//thrown if a child window(s) was already closed.
function closeWindows() {
var openCount = openWindow.length;
for(r=openCount-1;r>=0;r--) {
openWindow[r].close();
}
}
//Open a new child window and add it to the tracker.
function open1() {
win1 = window.open("http://www.yahoo.com");
trackOpen(win1);
}
//Open a different child window and add it to the tracker.
function open2() {
win2 = window.open("http://www.google.com");
trackOpen(win2);
}
//Open whatever the user enters and add it to the tracker
function open3() {
var newURL = document.getElementById("url").value;
var win3= window.open(newURL);
trackOpen(win3);
}
</script>
<input type="button" value="Open 1" onclick="open1()">
<input type="button" value="Open 2" onclick="open2()">
<input type="button" value="Focus 1" onclick="win1.focus()">
<input type="button" value="Focus 2" onclick="win2.focus()">
<input type="button" value="Close 1" onclick="win1.close()">
<input type="button" value="Close 2" onclick="win2.close()">
URL: <input type="text" id="url"> <input type="button" value="Open URL" onclick="open3()">
<input type="button" value="Close All" onclick="closeWindows()">
</body>
</html>
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